We use the formula d = rt where d = distance, r = rate, t = time
Equation for Sam:


Equation for Sam's father:

d = (12)(t - 0.33)
d = 12t - 4
Since Sam and his father have the same distance from their home to Sam's school, then
2t = 12t - 4
4 = 12t - 2t
4 = 10t
4/10 = t
t = 0.4 hrs or 24 mins
Sam travel 24 mins from home to school and his father travel 4 mins from home to school. Therefore, it was about 8:24 when Sam's father give the project to Sam.
The answer is $15.86
You find this by doing 2 and 3/5 or 2.6 times 6.10 getting an answer of $15.86
Answer:
14.9 km/hr
Step-by-step explanation:
We know
Speed = Distance/ Time
v = 82km / 5.5 hr
v = 14.90 km/hr
Ok
first of all, for q(x)/p(x)
if the degree of q(x) is less than the degree of p(x),then the horizontal assemtote is 0
then simplify
any factors you factored out is now a hole, remember them
to find the vertical assemtotes of a function, set the SIMPLIFIED denomenator equal to 0 and solve
so
y=(x-5)/(x^2-1)
q(x)<p(x)
horizontal assemtote is y=0
no factors to simplify so no holes
set denomenator to 0 to find vertical assemtote
x^2-1=0
(x-1)(x+1)=0
x-1=0
x=1
x+1=0
x=-1
the horizontal assemtotes are x=1 and -1
On a number line 1.77 would be located between 1 and 2 but it would be closer to 2 than 1.
<h3>Where would 1.77 be located?</h3>
A number line is used to show the positioning of numbers. 1.77 is between 1 and 2. So, it would be located between 1 and 2 on the number line. Because 1.77 can be rounded off to 2, it would be closer to 2.
To learn more about number lines, please check: brainly.com/question/13189025
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