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andrew-mc [135]
2 years ago
14

Can anyone help me please? i have 14 more minutes to finish this can anyone help?

Mathematics
2 answers:
valentinak56 [21]2 years ago
5 0

Answer:

B

Step-by-step explanation:

A is 3-2 which is 1, not 5.

C is 3(2), which is 6, not 5.

D is 6, which is not 5.

-hope it helps

yarga [219]2 years ago
4 0

Answer:

B

Step-by-step explanation:

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To use the Bayes classifier, we have to find the class (kk) for whichpk(x)=πk(1/2π−−√σ)e−(1/2σ2)(x−μk)2∑Kl=1πl(1/2π−−√σ)e−(1/2σ2)(x−μl)2=πke−(1/2σ2)(x−μk)2∑Kl=1πle−(1/2σ2)(x−μl)2pk(x)=πk(1/2πσ)e−(1/2σ2)(x−μk)2∑l=1Kπl(1/2πσ)e−(1/2σ2)(x−μl)2=πke−(1/2σ2)(x−μk)2∑l=1Kπle−(1/2σ2)(x−μl)2is largest. As the log function is monotonally increasing, it is equivalent to finding kk for whichlogpk(x)=logπk−(1/2σ2)(x−μk)2−log∑l=1Kπle−(1/2σ2)(x−μl)2log⁡pk(x)=log⁡πk−(1/2σ2)(x−μk)2−log⁡∑l=1Kπle−(1/2σ2)(x−μl)2is largest. As the last term is independant of kk, we may restrict ourselves in finding kk for whichlogπk−(1/2σ2)(x−μk)2=logπk−12σ2x2+μkσ2x−μ2k2σ2log⁡πk−(1/2σ2)(x−μk)2=log⁡πk−12σ2x2+μkσ2x−μk22σ2is largest. The term in x2x2 is independant of kk, so it remains to find kk for whichδk(x)=μkσ2x−μ2k2σ2+logπkδk(x)=μkσ2x−μk22σ2+log⁡πkis largest.
ng expression
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2 years ago
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