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elixir [45]
2 years ago
14

The total number of victories for a football team exceeds the number of defeats by 4, with no draws. Knowing that if 44 jojos, h

ow many victories were there?
Mathematics
1 answer:
Leno4ka [110]2 years ago
7 0

Answer: 24

Step-by-step explanation:

Let the number of defeats be represented by x.

Since the total number of victories exceeds the number of defeats by 4, then the number of victories will be:

= x + 4

We then add the number of victories and losses together and equate them to 44. This will be:

x + x + 4 = 44

2x + 4 = 44

2x = 44 - 4

2x = 40

x = 40/2

x = 20

Therefore number of victories will be:

= x + 4

= 20 + 4

= 24

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Answer:

5 3/8

Step-by-step explanation:

3 1/8 ÷(x−4 7/28 )= 17/18 +1 5/6

Get a common denominator for the right side

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Copy dot flip

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Simplifying the fractions

9/8 + 4 1/4 = x

Getting a common denominator

9/8 + 4 2/8 =x

4 11/8 =x

4 + 8/8+3/8 =x

5 3/8

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