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Olenka [21]
3 years ago
8

Points C and D are 884884 statute miles apart. How far apart are C and D in nautical​ miles? Assume the radius of the earth at t

he equator is approximately 3956 statute miles.
Mathematics
1 answer:
sineoko [7]3 years ago
7 0
I think this problem gave the data for the radius of earth so that we will know the conversion ratio between statute miles and nautical miles. However, you can simply search that. There are 1.15 statute miles in 1 nautical mile. Hence,

Distance in nautical miles = <span>884884 statute miles * 1 nautical mile/1.15 statute miles
<em>Distance =769,464.35 nautical miles</em></span>
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Answer quick for my hw pls
Readme [11.4K]

Answer:

day 14 , 450 dollars

Step-by-step explanation:

We called x is the number of days

Zippy Rent-a-car: 25x + 100

Speedy Rent-a-car: 30x + 30

25x + 100 = 30x + 30

25x -30x = 30 - 100

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tekilochka [14]

Answer:

9x2, 6x3, 1x18

Step-by-step explanation:

9x2=18

6x3=18

1x18=18

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in a program designed to help patients stop smoking 232 patients were given sustained care and 84.9% of them were no longer smok
grandymaker [24]

Answer:

z=\frac{0.849 -0.8}{\sqrt{\frac{0.8(1-0.8)}{232}}}=1.869  

p_v =2*P(Z>1.869)=0.0616  

If we compare the p value obtained and the significance level given \alpha=0.05 we see that p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the proportion of adults were no longer smoking after one month is not significantly different from 0.8 or 80% .  

Step-by-step explanation:

1) Data given and notation

n=232 represent the random sample taken

X represent the adults were no longer smoking after one month

\hat p=0.849 estimated proportion of adults were no longer smoking after one month

p_o=0.80 is the value that we want to test

\alpha=0.05 represent the significance level

Confidence=95% or 0.95

z would represent the statistic (variable of interest)

p_v represent the p value (variable of interest)  

2) Concepts and formulas to use  

We need to conduct a hypothesis in order to test the claim that the true proportion is 0.8.:  

Null hypothesis:p=0.8  

Alternative hypothesis:p \neq 0.8  

When we conduct a proportion test we need to use the z statistic, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.

3) Calculate the statistic  

Since we have all the info requires we can replace in formula (1) like this:  

z=\frac{0.849 -0.8}{\sqrt{\frac{0.8(1-0.8)}{232}}}=1.869  

4) Statistical decision  

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.  

The significance level provided \alpha=0.05. The next step would be calculate the p value for this test.  

Since is a bilateral test the p value would be:  

p_v =2*P(Z>1.869)=0.0616  

If we compare the p value obtained and the significance level given \alpha=0.05 we see that p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the proportion of adults were no longer smoking after one month is not significantly different from 0.8 or 80% .  

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Answer:

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Step-by-step explanation:

hope this helps :) have a nice day :)

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Step-by-step explanation:

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