Answer:
-32/27
Step-by-step explanation:
-12 - 20 -32 -32
----------- = ----------- = ----------
15 - (-12) 15 + 12 27
The coordinates of the point P which divides the line segment AB made by the points A(-7,2) and B(9,-6) is (x,y) = (5,-4)
<h3>What is the coordinate of the point which divides a line segment in a specified ratio?</h3>
Suppose that there is a line segment
such that a point P(x,y) lying on that line segment
divides the line segment
in m:n, then, the coordinates of the point P is given by:

where we have:
- the coordinate of A is

- and the coordinate of B is

We're given that:
- Coordinate of A is
= (-7,2) - Coordinate of B is
= (9.-6) - The point P lies on AB such that AP:BP=3:1 (so m = 3, and n = 1)
Let the coordinate of P be (x,y), then we get the values of x and y as:

Thus, the coordinates of the point P which divides the line segment AB made by the points A(-7,2) and B(9,-6) is (x,y) = (5,-4)
Learn more about a point dividing a line segment in a ratio here:
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Answer:
v
Step-by-step explanation:
Answer:
a
Step-by-step explanation:
Recall that the "point-slope" form of a linear equation may be expressed as
y = mx + b,
where m is the gradient.
If m is negative, the gradient is negative.
If m is positive, the gradient is positive.
In our case, if we consider option A,
x + 3y = -2 (rearranging)
3y = -x -2
y = (-1/3) x - (2/3)
if we compare this to the general equation at the top, we can see that
gradient, = m = (-1/3) which is negative.
hence option a has a negative gradient.
Perpendicular to the line y = 5x - 9
m= -1/5
the line passing through the point (1, 4):
4=-1/5*1+q
q= 21/5
the equation is:
y= -1/5x +21/5
or
x+5y-21=0