The speed of slower car is 45 mph and faster car is 50 mph.
Step-by-step explanation:
Given,
Distance covered by both cars = 190 miles
Time taken by both of them = 2 hours
Let,
x be the speed of slower car.
Speed of faster car = x+5
Combined speed = x+x+5 = 2x+5
We know that;
Distance = Speed * Time
Dividing both sides by 4
Speed of slower car = 45 miles per hour
Speed of faster car = 45+5 = 50 miles per hour
The speed of slower car is 45 mph and faster car is 50 mph.
Keywords: speed, distance
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You can put 6 cookies in each bag with 12 bags in total.
Do, 72 Divided by 6 and you get 12.
Hope it helps
The height of the kite above the ground is 58.68 ft
Let x be the height of the kite above Chee's hand.
The height of the kite above Chee's hand, the string and the horizontal distance between Chee and the kite form a right angled triangle with hypotenuse side, the length of the string and opposite side the height of the kite above Chee's hand.
Since we have the angle of elevation from her hand to the kite is 29°, and the length of the string is 100 ft.
From trigonometric ratios, we have
tan29° = x/100
So, x = 100tan29°
x = 100 × 0.5543
x = 55.43 ft.
Since Chee's hand is y = 3.25 ft above the ground, the height of the kite above the ground, L = x + y
= 55.43 ft + 3.25 ft
= 58.68 ft to the nearest hundredth of a foot
So, the height of the kite above the ground is 58.68 ft
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Mode are repeating numbers in a sequence therefore 23 is your mode
Any odd number can be expressed by 2n+1.
For example,
2n+1=111
2n=110
n=110/2=55
means that 111 is 2n+1 for n=55
Thus if an odd number is 2a+1, the next few numbers are as follows:
2a+1, 2a+2, 2a+3, 2a+4, 2a+5
So 2a+1, 2a+3 and 2a+5 are 3 consecutive odd numbers.
Back to our problem:
three consecutive odd numbers whose sum is 63 are:
(2n+1)+(2n+3)+(2n+5)=63
6n+9=63
6n=63-9=54
n=54/6=9
2n+1=2*9+1=18+1=19, the 2 next odd numbers are 21 and 23
Answer: 19, 21, 23
