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3 years ago

Danna's age is 6 years less than 8 times Tessa's age. If Tessa's age is x years, which expression best shows Danna's age?

Mathematics

2 answers:

KonstantinChe [14]3 years ago

8 0

The correct equation is

8x-6

Hope this helps! Comment if you have questions on how I got it! :)

Marat540 [252]3 years ago

3 0

6 - 8x is the correct answer

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Calculate the quotient below and give your answer in scientific notation. 2.64*10^-3\8.0*10^0

Zolol [24]

Answer:

The quotient of: $\frac{2.64\cdot 10^{-3}}{8.0\cdot 10^0}$ is: $\mathbf{3.3\times 10^{-4}}$

Step-by-step explanation:

We need to find quotient of: $\frac{2.64\cdot 10^{-3}}{8.0\cdot 10^0}$

We know that $10^0=1$

Now solving:

$\frac{2.64\cdot 10^{-3}}{8.0\cdot 10^0}\\=\frac{2.64\cdot 10^{-3}}{8.0}\\=\frac{0.00264}{8}\\=0.00033$

Writing it in scientific notation

$0.00033\\=3.3\times10^{-4}$

So, the quotient of: $\frac{2.64\cdot 10^{-3}}{8.0\cdot 10^0}$ is: $\mathbf{3.3\times 10^{-4}}$

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3 years ago

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Anon25 [30]

Step-by-step explanation:

Step 1: Set x equal to 0 to find the y-int

$y = 10000(1 - 0.40)$ → Not an exponential equation

$y=10000(1-0.40)^0$ → 10,000 → Works for first test

$y = 10000(1-0.60)^0$ → 10,000 → Works for first test

$y = 10000(1+0.40)^0$ → 10,000 → Works for first test

Step 2: Set x equal to 1

$y=10000(1-0.40)^1$ → 6,000 → Works for second test

$y = 10000(1-0.60)^1$ → 4,000 → Does not work for the second test

$y = 10000(1+0.40)^1$ → 14,000 → Does not work for the second test

Answer: The answer is Option B

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