A ball is thrown into the air with an upward velocity of 28ft/s. Its height h in feet after t seconds is given by the function h
= -16t^2 + 28t + 8
1 answer:
Answer:
In bold below.
Step-by-step explanation:
Find derivative which gives the velocity:
V = h' = -32t + 28
At maxm height V = 0 so
-32t + 28 = 0
Time to reach maxm height t = -28/-32 = 0.875 seconds.
So maxm height
= -16(0.875)^2 + 28*0.875 + 8
= 20.25 ft.
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