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Marrrta [24]
3 years ago
8

A packet of biscuits has a mass of 1 1/3 kg. Jason eats 2/5 of the packet. What is the mass of biscuits left?

Mathematics
1 answer:
BabaBlast [244]3 years ago
6 0
11 / 3 = 55 / 15;
2 / 5 = 6 / 15;
So. 11 / 3 - 2 / 5 = 55 / 15 - 6 / 15 = 49 / 15 = 3.26 kg is the mass of biscuits left.
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2=ln(x+7) solve for x
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Answer:

e^2 -7 = x

Step-by-step explanation:

2=ln(x+7)

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e^2 = e^ln (x+7)

The e^ln cancel

e^2 = x+7

Subtract 7 from each side

e^2 -7 = x +7-7

e^2 -7 = x

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3 years ago
Find the average speed. 700 feet in 1 minute 10 seconds
tresset_1 [31]
I believe that the answer is 20.45
4 0
4 years ago
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Find the constant of proportionalty from the equation y=7.25x
Lelechka [254]
Its the number that multiplies x

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7 0
4 years ago
Help please. Thanks in advance
anygoal [31]
Since they want only the coordinates of the vertices. You only care about where the lines intersect, the greater than, less than signs are irrelevant.

Get each equation in 'y=mx+b' form
1)  y = -x + 9
2)  y = 2x-21
3)  y = -4x +15

Now you can set any 2 equations equal to each other and solve for 'x'.
This will be the 'x' coordinate of the point where the 2 lines intersect.
You need 3 points, so you will need 3 different sets of 2 equations:

1) = 2)
2x -21 = -x+9
3x = 30
x = 10  -----> y = -(10)+9 = -1


1) = 3)
-x+9 = -4x+15
3x = 6
x = 2  -------> y = -(2) + 9 = 7

2) = 3)
2x - 21 = -4x+15
6x = 36
x = 6  ---------> y = 2(6) -21 = -9

Therefore the 3 intersecting points are:
(10,-1)
(2, 7)
(6, -9)
6 0
4 years ago
Dada la circunferencia de ecuación x 2 +y 2 -2x+4y-4=0, hallar el centro y el radio.
Anna11 [10]

La forma estándar de una ecuación de un círculo es% 28x-h% 29% 5E2 +% 2B +% 28y-k% 29% 5E2 + = + r% 5E2

donde Pt (h, k) es el centro y r es el radio

x ^ 2 + y ^ 2-10x + 4y + 4 = 0

completando los cuadrados para ponerlos en la forma estándar

x ^ 2 -10x + y ^ 2 + 4y + 4 = 0

(x-5) ^ 2-25 + (y +2) ^ 2-4 + 4 = 0

 (x-5) ^ 2 + (y + 2) ^ 2 = 25

El centro es (5, -2) radio = 5

4 0
3 years ago
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