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2 years ago

Simplify the complex fraction. 3/4 2/5

Mathematics

1 answer:

laiz [17]2 years ago

8 0

Answer:

assuming you meant (3/4)/(2/5)

15/8 or 1 7/8

Step-by-step explanation:

use a calculator

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Plz help will be marked BRAINLIEST and thanks <br><br> Jwhdbendhdbe

morpeh [17]

Answer:

BDC 37°

CDE 143°

FDE 37°

FDA 90°

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3 0

2 years ago

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A decorative window is made up of a rectangle with semicircles at either end. The ratio of AD to AB is 3:2 and AB is 30 inches.

scZoUnD [109]

Answer: The required ratio will be

$84:1034$

Step-by-step explanation:

Since we have given that

Ratio of AD to AB is 3:2

Length of AB = 30 inches

So, it becomes

$2x=30\\\\x=\frac{30}{2}=15\ inches$

So, Length of AD becomes

$3x=3\times 15=45\ inches$

Now, at either end , there is a semicircle.

Radius of semicircle along AB is given by

$\frac{30}{2}=15\ inches$

So, Area of semicircle along AB and CD is given by

$2\times \frac{\pi r^2}{2}\\\\=\frac{22}{7}\times 15\times 15\\\\=\frac{4950}{7}\ in^2$

Radius of semicircle along AD is given by

$\frac{45}{2}=22.5\ inches$

Area of semicircle along AD and BC is given by

$2\times \frac{1}{2}\pi r^2\\\\=\frac{22}{7}\times \frac{45}{2}\times \frac{45}{2}\\\\=\frac{445500}{28}\ in^2$

And the combined area of the semicircles is given by

$\frac{4950}{7}+\frac{445500}{28}\\\\=\frac{465300}{28}\ in^2$

Area of rectangle is given by

$Length\times width\\\\=AD\times AB\\\\=45\times 30\\\\=1350\ in^2$

Hence, Ratio of the area of the rectangle to the combined area of the semicircles is given by

$1350:\frac{465300}{28}\\\\=1350\times 28:465300\\\\=37800:465300\\\\=84:1034$

Hence, the required ratio will be

$84:1034$

8 0

2 years ago

Which expression is a monomial?

creativ13 [48]

I need options but this is an example of a monomial:

(2x^2)

5 0

2 years ago

2.5 divided by 0.5 what would that be

Alex17521 [72]

Answer:

1.25

Step-by-step explanation:

1/2 of 2.5 is 1.25

Think of it as the following

250 divided by 2 is 125 because 125+125=250

4 0

2 years ago

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Use a factor and zero product property to solve the following equation 6x(x+4)=0

Rina8888 [55]

$6x(x+4)=0 \\
6x=0 \ \lor \ x+4=0 \\
x=0 \ \lor \ x=-4 \\
\boxed{x=0 \hbox{ or } x=-4}$

4 0

2 years ago