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Murljashka [212]
3 years ago
13

I will mark as brainliest:)

Mathematics
1 answer:
Aliun [14]3 years ago
8 0

Answer:

Cube C

Step-by-step explanation:

{ \sf{because \: it \: is \: identical}}

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find the circumference of a circle that has an area of 452.16 square meters. (Use 3.1416 as the value of π.)
IceJOKER [234]
(1) circumference of a circle = 2π.R
(2) area of a circle = π.R²

Area = 452.16 m² (given), so we can calculate the radius:
452.16 = π.R²
452.16/π = R²

143.92 = R²  → R =√143.92 ≈ 12 m
Having R = 12, now we can calculate the circumference :

circumference of a circle = 2π.R = 2.π.12 = 75.41 m

3 0
3 years ago
4. Mario was asked to find the GCF of 15, 30, and 45. What number did he find? A. 15 C. 45 B. 30 D. 60
SVETLANKA909090 [29]
4. is A 15
5. is C 12
6. is B 4, 8, 12, 16

hope this helps :)
7 0
3 years ago
Read 2 more answers
Please help me I think the answer is 12 cm .
-Dominant- [34]

You can find the value of the hypotenuse if you apply the Pythagorean Theorem, which is show below:


 h²=a²+ b² ⇒ h=√(a² + b²)


 h: hypotenuse (the opposite side of the right angle and the longest side of the triangle).

 a and b: legs (the sides that form the right angle).


 Then, you have:


 h²=a² + b²

 h²=12²+12²

 h=√ ((12)² + (12)²)

 h=12√2


 What is the lenght of the hypotenuse?


 The answer is: The length of the hypotenuse is 12√2

6 0
3 years ago
Simplify the expression (-8)^-3x15^0
avanturin [10]
The answer is -1 over 512 (fraction form)
ANSWER: -1/512
5 0
3 years ago
I need help with this math question
givi [52]

Answer:

a.) y = 3/(2ˣ)

b.) y = 1/(2ˣ)

c.) y = (π^π)ˣ

d.) y = (1/27)(1/√(3))ˣ

e.) y = .002908/(.119025ˣ)

f.) y = .00000004808/(.0413ˣ)

Step-by-step explanation:

Concept need to know is:

  • a negative exponent will flip the numerator with the denominator
  • a fraction as an exponent is just a root. so if the exponent is x^(1/2) then the root is 2 and x^(1/3) is a cube root
  • adding and subtracting exponent is the same thing as multiplying the same base.
  • so x^(1+2) = (x^1)(x^2)
  • and x^(1-2) = (x^1)(x^-2)

7 0
3 years ago
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