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Arturiano [62]
2 years ago
10

Write the equation of the perpendicular bisector of the line segment connecting (10, 3) to (6, -13)

Mathematics
1 answer:
Feliz [49]2 years ago
3 0

Answer:

y = -1/4x - 3

Step-by-step explanation:

Halfway through would be:

(10 + 6 / 2, -13 + 3 / 2) --> (8, -5)

The slope of the line that goes through (10, 3) and (6, -13) is -13 - 3 / 6 - 10 = -16 / -4 = 4.

That means the slope of the line that is perpendicular would be the negative reciprocal of 4, which is -1/4.

Put this in point slope form with slope = -1/4 and point = (8, -5):

y + 5 = -1/4(x - 8)

y + 5 = -1/4x + 2

y = -1/4x - 3

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8 0
3 years ago
12x^3-11x^2+9x+18 divided by 4x+3
atroni [7]
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12x^3-11x^2+9x+18/4 x +3

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3 years ago
Which graph represents x
Maurinko [17]
The answer is the second graph.

\frac{x}{3} \leq 2
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4 0
3 years ago
Read 2 more answers
the length of the shadow of a pole on level ground increases by 90m when the angle of elevation of the sun changes from 58 degre
Anarel [89]

Answer:

The height of the pole is 167 m

Step-by-step explanation:

The given parameters are;

Increase  in the length of the shadow = 90 m

Initial angle of elevation of the Sun = 58°

Final angle of elevation of the Sun = 36°

We have a triangle formed by the change in the length of the shadow and the rays from the two angle of elevation to the top of the pole giving an angle 22° opposite to the increase  in the length of the shadow  

We have by sin rule;

90/(sin (22°)  = (Initial ray from the top of the pole to the end of the shadow's length)/(sin(122°)

Let the initial ray from the top of the pole to the end of the shadow's length = l₁

90/(sin (22°)  = l₁/(sin(122°)

l₁ = 90/(sin (22°) ×(sin(122°) = 283.3 m

Therefore;

The height of the pole = 283.3 m × sin(36°) = 166.52 m

The height of the pole= 167 m to three significant figures.

3 0
3 years ago
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