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Lena [83]
3 years ago
5

-

- 3\pi + w = 2\pi" align="absmiddle" class="latex-formula">
Mathematics
1 answer:
pantera1 [17]3 years ago
4 0

Isolate the w. Note the equal sign. What you do to one side, you do to the other.

Add 3π to both sides

- 3π (+3π) + w = 2π (+3π)

w = 2π + (3π)

w = 5π

w = 5π is your answer

hope this helps

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Answer:

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Step-by-step explanation:

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See attachment for triangles

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Substitute 8 for Area

8 = \frac{1}{2} * PQ * PN

PQ * PN = 16

The area of LPQ is calculated as:

Area = \frac{1}{2} * PQ * LP

Substitute 16 for Area

16= \frac{1}{2} * PQ * LP

From the attachment:

PN + LP =LN

Make LP the subject

LP = LN -PN

So:

16= \frac{1}{2} * PQ * (LN -PN)

We have:

16= \frac{1}{2} * PQ * (LN -PN) and PQ * PN = 16

Equate both expressions:

\frac{1}{2} * PQ *(LN - PN) = PQ * PN

Divide both sides by PQ

\frac{1}{2} (LN - PN) = PN

Multiply both sides by 2

LN - PN = 2PN

LN= 3PN

Since PNQ is similar to LNM, the following equivalent ratios exist:

\frac{LM}{PQ} = \frac{LN}{PN}

Substitute LN= 3PN

\frac{LM}{PQ} = \frac{3PN}{PN}

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Area = \frac{1}{2} * LM * LP

This gives:

Area = \frac{1}{2} * 3PQ * LP

Area = 3 *\frac{1}{2} *PQ * LP

Recall that:

16= \frac{1}{2} * PQ * LP

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Area = 3 *16

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