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3 years ago

In ΔEFG, g = 6.7 inches, e = 5.9 inches and ∠F=70°. Find the length of f, to the nearest 10th of an inch.

Mathematics

2 answers:

vovangra [49]3 years ago

8 0

Step-by-step explanation:

Using cosine rule,

f² = g² + e² - 2(g)(e)(cosF) = 6.7² + 5.9² - 2(6.7)(5.9)(cos70°)

= 52.6598 in²

Hence f = 7.3 in.

KATRIN_1 [288]3 years ago

3 0

Answer: 7.3

Step-by-step explanation:

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3 years ago

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@###GEOMETRY, SEE PHOTO! PLEASE HELP ASAP!####@

Dafna11 [192]

Since this is a right triangle, we can use our trigonometric functions to solve for x.

Since we know the adjacent side and hypotenuse, we will use cosine.

Based on the function $\cos(x) = \frac{adj}{hyp}$ , we can solve for x. The adjacent side is 7 and the hypotenuse is 12. Plugging this in, we get $\cos(x) = \frac{7}{12}$ .

Now, we must use our inverse trigonometric functions to solve for x:
$\cos^{-1}(\cos(x)) = \cos^{-1}(\frac{7}{12})$

The inverse cosine and cosine on the left side cancel, leaving you with:
$x = \cos^{-1}(\frac{7}{12}) = \boxed{54.3^{\circ}}$

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4 years ago

Given f(x)=x-10 . what is f(-7)?

Tomtit [17]

F(-7) = -7 - 10

f(-7) = -17

Hope I helped!

Let me know if you need anything else!

<span>~ Zoe (Rank:'Genius')</span>

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3 years ago