Answer:
AaBb, AABb, AaBB, AABB, Aabb, aaBb, AAbb, aaBB, aabb.
Explanation:
Gene A conditions pigment type.
Gene B determines whether the pigment of A will be deposited.
Heterozygous black individuals will have the genotype AaBb.
Two heterozygous black individuals were crossed:
AaBb x AaBb
Progeny:
4 AaBb - Black
2 AABb - Black
2 AaBB - Black
1 AABB - Black
2 Aabb - yellow
2 aaBb - yellow
1 AAbb - brown
1 aaBB - brown
1 aabb - brown
<em>Hence, the genotypes of the offspring are:</em>
AaBb, AABb, AaBB, AABB, Aabb, aaBb, AAbb, aaBB, aabb.
See the attached image for the Punnet's square result of the cross.