6th time i posted this, could someone help me?
1 answer:
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You are correct! The problems that can arise with a function domain are:
- Denominators that become zero
- Even-degree roots with negative input
- Logarithms with negative or zero input
In this case, you have a denominator, and you don't have roots nor logarithms. This means that your only concern must be the denominator, specifically, it cannot be zero.
And you simply have
So, the domain of this function includes every number except 3.
Given:
Equation of line .
To find:
The equation of line that goes through the point ( − 21 , 2 ) and is perpendicular to the given line.
Solution:
The given equation of line can be written as
Slope of line is
Product of slopes of two perpendicular lines is -1. So, slope of perpendicular line is
Now, the slope of perpendicular line is and it goes through (-21,2). So, the equation of line is
Therefore, the required equation in slope intercept form is .
We want to find 
, for
.
Recall the product rule: for 2 differentiable functions f and g, the derivative of their product is as follows:
.
Thus,
![y'=[(x^2+2)^3]'[(x^3+3)^2]+[(x^3+3)^2]'[(x^2+2)^3]\\\\ =3(x^2+2)^2(x^3+3)^2+2(x^3+3)(x^2+2)^3](https://tex.z-dn.net/?f=y%27%3D%5B%28x%5E2%2B2%29%5E3%5D%27%5B%28x%5E3%2B3%29%5E2%5D%2B%5B%28x%5E3%2B3%29%5E2%5D%27%5B%28x%5E2%2B2%29%5E3%5D%5C%5C%5C%5C%20%3D3%28x%5E2%2B2%29%5E2%28x%5E3%2B3%29%5E2%2B2%28x%5E3%2B3%29%28x%5E2%2B2%29%5E3)
Answer: A)
.
Recall the product rule: for 2 differentiable functions f and g, the derivative of their product is as follows:
Thus,
Answer: A)
For this case we have that the commutative property establishes that the order of the factors does not alter the product. Example:
Then we have the following options illustrate the property:
It is necessary to emphasize that option b illustrates the associative property and in option c equality is not fulfilled
Answer:
Option A, D, E, F