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Bogdan [553]
2 years ago
5

6th time i posted this, could someone help me?

Mathematics
1 answer:
fiasKO [112]2 years ago
7 0

Answer:

it's blurry

Step-by-step explanation:

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Please Help answer has much as you can
navik [9.2K]

Answer:

24 is the answer ok 21/7

is 3 and multiply it with 8 that is 24

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q = -3

4 0
3 years ago
X = 5y/(z-4y) <br><br> make y subject
Margarita [4]

Answer:

y=2x/5-4x

Step-by-step explanation:

multiply z-4y on both sides,match the Ys together and then make y common

3 0
2 years ago
Rewrite, differentiate and simplify:<br> 3/(2x)^3
Llana [10]

\frac{dy}{dx} = - \frac{9}{8x^{4} }

let y = \frac{3}{(2x)^{3} } = \frac{3}{8} x^{-3}

differentiate using the power rule

\frac{d}{dx} (ax^{n} ) = nax^{n-1}

\frac{dy}{dx} = - \frac{9}{8}x^{-4} = - \frac{9}{8x^{4} }


8 0
3 years ago
Which ordered pair is a solution of the equation y equals x minus 3
Rom4ik [11]
Y = x-3

Basically you just need to plug in an x value and solve for y
y = x - 3
y = (4) - 3
y = 1

In this case, the ordered pair of this equation would be (4, 1)

You can do this given any x or y coordinate

Hope this helps 
6 0
3 years ago
the slope of a line passing through h (-2, 5) is -3/4. Which ordered pair represents a point on this line? ​
rosijanka [135]

Answer:

A

Step-by-step explanation:

Calculate the slope of the given points with the point (- 2,  5 )

If the slope is - \frac{3}{4} then the point is on the line

Calculate slope m using the slope formula

m = \frac{y_{2}-y_{1}  }{x_{2}-x_{1}  }

with (x₁, y₁ ) = (- 2, 5) and (x₂, y₂ ) = (6, - 1)

m = \frac{-1-5}{6+2} = \frac{-6}{8} = - \frac{3}{4} ← point (6, - 1) is on the line

Repeat with (x₁, y₁ ) = (- 2, 5 ) and (x₂, y₂ ) = (2, 8)

m = \frac{8-5}{2+2} = \frac{3}{4} ← point (2, 8) is not on the line

Repeat with (x₁, y₁ ) = (- 2, 5) and (x₂, y₂ ) = (- 5, 1)

m = \frac{1-5}{-5+2} = \frac{-4}{-3} = \frac{4}{3} ← point (- 5, 1) is not on the line

Repeat with (x₁, y₁ ) = (- 2, 5) and (x₂, y₂ ) = (1, 1)

m = \frac{1-5}{1+2} = - \frac{4}{3} ← point (1, 1) is not on the line

Thus the point on the line is (6, - 1 ) → A

4 0
3 years ago
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