Answer:
C. 2x^4; E. -5x
Step-by-step explanation:
P(x) = x^3 − x − 2 and Q(x) = x^2 + 2x + 1
P(x) * Q(x) = (x^3 − x − 2)(x^2 + 2x + 1) =
= x^5 + 2x^4 + x^3 - x^3 - 2x^2 - x - 2x^2 - 4x - 2
= x^5 + 2x^4 - 4x^2 - 5x - 2
Answer: C. 2x^4; E. -5x
It would be the graph with the line at the 3 on the y axis and with points going up 4 and over 1
Answer:
x=30
Step-by-step explanation:
you would call those alternate exterior angles meaning that they are the same angle, so all you have to do is reverse the equation meaning you do 75-15=60 and you would then divide by 2 to get X so 60/2=30, so <u>x=30</u>
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First, let's rewrite to make this problem easier.
1^2 - a^2b^2
Then we must multiply the terms with equal exponents with their bases.
1^2-(ab)^2
Using the factor: a^2 - b^2=(a-b)(a+b)
We can factor using that expression.
(1-ab) x (1+ab)
After factoring, this has been our solution.
Solution: (1-ab) x (1+ab)
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- Tutor John
