Given:
7 red candies
9 blue candies
12 pink candies
Condition:
Number of bags that has equal number of candies.
We can do 7 bags with 1 colored candy each. There will be an excess of 2 blue candies and 5 pink candies.
We can do 4 bags with 1 red candy, 2 blue candies, 3 pink candies. There will be an excess of 3 red candies and 1 blue candy.
We can do 3 bags with 2 red candies, 3 blue candies, 4 pink candies. There will be an excess of 1 red candy.
Answer:
3p - 15
Step-by-step explanation:
5p - 2p = 3p
-5 - 10 = -15
3p + - 15 = 3p - 15
A represents a function
This is the way
Answer:
Step-by-step explanation:
2(x^2 + 10x + 25) + 3
2x^2 + 20x + 50 + 3
2x^2 + 20x + 53
S ( s + 1)/ 2
so <span>The sum of the first 100 positive numbers
100(100 + 1) / 2
= 50(101)
= 5050</span>
