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Karo-lina-s [1.5K]
3 years ago
9

in math class, the girl to boy ratio is 8 to 6.1f there are 24 girls in the cláss, how many boys are there?

Mathematics
1 answer:
daser333 [38]3 years ago
8 0

Answer:

26 boys

Step-by-step explanation:

26 boys

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HELP WITH PART C‼️Any questions ask
saveliy_v [14]

Answer:

they are alike because they both include a variable and they both have their totals in currency form. They are different because they use different variables.

Step-by-step explanation:

6 0
4 years ago
Ken has a pole that is 26 inches long. He wishes to cut it into two pieces so that one piece will be 8 inches longer than the ot
Yuliya22 [10]

Answer:

9 inches

Step-by-step explanation:

Do the question algebraically, represented by this equation:

let x be the shorter piece

x + (x + 8) = 26                      (longer piece is 8 units longer)

Remove brackets

x + x + 8 = 26                 Combine like terms              

2x + 8 = 26                   Start isolating "x"

2x + 8 - 8 = 26 - 8           Subtract 8 from both sides

2x = 18

2x/2 = 18/2           Divide both sides by 2

x = 9                    shorter piece

The shorter piece would be 9 inches.

If you needed the longer piece too:

longer piece = x + 8

x + 8

= 9 + 8

= 17

The longer piece would be 17 inches.

Check your answer:

Longer + Shorter = 26           Substitute the lengths

17 + 9 = 26                    Add

26 = 26                same number

LS = RS                left side equals right side

The answer is correct.

3 0
4 years ago
A number divided by the sum of three and four
polet [3.4K]

Answer:

(3t + 4) / (4 - r)

Step-by-step explanation:

5 0
3 years ago
The seventh term of an arithmetic progression is equal to twice the fifth term. The sum
mario62 [17]

Answer:

a₁ = - 24

Step-by-step explanation:

The n th term of an AP is

a_{n} = a₁ + (n - 1)d

where a₁ is the first term and d the common difference

Given a₇ = 2a₅ , then

a₁ + 6d = 2(a₁ + 4d) = 2a₁ + 8d ( subtract 2a₁ + 8d from both sides )

- a₁ - 2d = 0 → (1)

The sum to n terms of an AP is

S_{n} = \frac{n}{2} [ 2a₁ + (n - 1)d ]

Given S_{7} = 84 , then

\frac{7}{2} (2a₁ + 6d) = 84

3.5(2a₁ + 6d) = 84 ( divide both sides by 3.5 )

2a₁ + 6d = 24 → (2)

Thus we have 2 equations

- a₁ - 2d = 0 → (1)

2a₁ + 6d = 24 → (2)

Multiplying (1) by 3 and adding to (2) will eliminate d

- 3a₁ - 6d = 0 → (3)

Add (2) and (3) term by term to eliminate d

- a₁ = 24 ( multiply both sides by - 1 )

a₁ = - 24

6 0
3 years ago
<img src="https://tex.z-dn.net/?f=4x%20-%20%20%7Bx%7D%5E%7B3%7D%20" id="TexFormula1" title="4x - {x}^{3} " alt="4x - {x}^{3} "
nydimaria [60]
X(2+x)(2-x) I think that’s correct
3 0
3 years ago
Read 2 more answers
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