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2 years ago

Work out the area of this circle.

Mathematics

1 answer:

Vlada [557]2 years ago

6 0

Answer:

530.998cm^2

Step-by-step explanation:

General formula for the area of a circle is πr^2

And π is given to be 3.142

R is 13 cm

So let's apply the formula

Area=3.142×(13^2)

Area=3.142×169

Area=530.998cm^2

So the area of the circle is 530.998cm^2

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Find all solutions to the equation secx(2 cosx-sqrt 2)=0

ollegr [7]

Hello,

We suppose x≠+/-π/2.

2cos x - √2=0
==>cos x=√2/2
==>x= π/4 or x=3π/4 (modulo 2π)

6 0

2 years ago

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the water works commission needs to know the mean household usage of water by the residents of a small town in gallons per day.

marin [14]

To determine the average water use, 109 people must be sampled.

1.9 gallons is the standard deviation.

E = 0.15 gallons maximum error

1.9 gallons on average

90% is the critical value.

1.645 is the 90% confidence interval.

sample size requirement,

n = (((z ÷ 2) × σ) ÷ E)²

n = (((1.645 ÷ 2) × 1.9) ÷ 0.15)²

n = ((0.8225 × 1.9) ÷ 0.15)²

n = (1.5627 ÷ 0.15)²

n = (10.418)²

n = 108.53 ≈ 109

As a result, the minimal sample size necessary to determine the mean water use = 109.

It is determined by dividing the average standard error by the squared of the sample size, and it decreases with increasing sample size. In other words, when the sample size is sufficiently big, the population mean approaches the population mean.

To learn more about the sample interval at

brainly.com/question/13664567?referrer=searchResults

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8 0

9 months ago

I need help with number 3

Marizza181 [45]

Area of circle = pi r^2 = 78.54
r^2 = 78.54 / pi = 25
r = 5 inches

Each line from centre of the circle to a point on the hexagon = 5 ins

so consider one of the 6 congruent triangles formed from these lines:-
Vertex angle = 60 degrees

sin 30 = 0.5s / 5 (where s = one side of the hexagon).
0.5s = 5*0.5 = 2.5
s = 2.5 / 0.5 = 5

So the perimeter of the hexagon is 6*5 = 30 inches

8 0

2 years ago

Solve the following system of equations:

PSYCHO15rus [73]

If we multiply the first equation by 2 we get
2x - 4y = 12
but the second equation is
2x - 4y = 10

2x - 4y can't have 2 different values so the are no solutions

7 0

2 years ago

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Drew jumped farther than all 4 students above but jumped shorter than 7 feet , 7 inches. How far could drew have jumped? Write s

S_A_V [24]

<h3>The distance covered by Drew in long jump is either 7 ft 5 inches OR 7 ft 6 inches.</h3>

Step-by-step explanation:

Here, the needed table is attached for the reference.

Now, as we can see from the table:

The distance covered by Cindy = 2 yards, 1 foot 3 inches

The distance covered by Tyrette = 7 feet, 2 inches

The distance covered by Nina = 2 yards, 1 foot, 1 inch

The distance covered by Monique = 7 feet, 4 inches

As we know : 1 yard = 3 feet

So, the distance covered by :

Cindy = 2 yards, 1 foot 3 inches = 3 ft x (2) + 1 ft + 3 in = 7 ft 3 in

Tyrette = 7 feet, 2 inches

Nina = 2 yards, 1 foot, 1 inch = = 3 ft x (2) + 1 ft + 1 in = 7 ft 1 in

Monique = 7 feet, 4 inches

So by comparing all distances, we can see that:

The maximum distances jumped by all four is 7 ft 4 inches.

The distance covered by Drew is less than 7 ft 7 in.

So, he must have jumped 7 ft 5 inches OR 7 ft 6 inches.

Hence, the distance covered by Drew in long jump is either 7 ft 5 inches OR 7 ft 6 inches.

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2 years ago