I think its either C or D give me one second to figure it out.
A - 3b = 4 . . . . (1)
a = b - 2 . . . . . (2)
Putting (2) into (1), we have
b - 2 - 3b = 4
-2b = 4 + 2 = 6
b = 6/-2 = -3
From (1), a = b - 2 = -3 - 2 = -5
Hence, solution = (-5, -3)
There's one unforgivable taboo that transcends just about every branch of mathematics, and that's dividing by zero. Division by zero is undefined, so any fraction with a zero in its denominator is by definition absurd. For what values of x would the denominators on either of those fractions be zero? Those will define the restrictions on your variable.
dont know wish i could help you :( sorry i hate when i can't answer a question it makes me feel bad
