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3 years ago

If -11 + N= -11, then N is the

Mathematics

1 answer:

Tamiku [17]3 years ago

4 0

Answer:

Additive Identity

Step-by-step explanation:

If you are adding an expression, but get the same result, then it's additive identity.

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Rotation 180 about the origin E(2,-2), J(1,2), R(3,3), S(5,2)

hammer [34]

E' (-2, 2) , J'(-1, -2) , R'(-3,-3) , S'(-5, -2)

6 0

3 years ago

I took a picture of the question

cluponka [151]

Answer:

27.5 inches^2

Step-by-step explanation:

Area of a triangle =

$\frac{bh}{2}$

Plugging in the equation,

$\frac{11 \times 5}{2} = \frac{55}{2} \\ \frac{55}{2} = 27.5$

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3 years ago

Solve the equation for y. 4x+y=-5

sesenic [268]

Y is 5! Good Luck Fam

6 0

3 years ago

Read 2 more answers

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Savatey [412]

Answer:

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3 years ago

Give the equation of the line perpendicular to y +7= -2(x - 6) through the<br> point (6,-3)

lilavasa [31]

<u>Note: this answer assumes the equation of the line can be put in slope-intercept form. </u>

Answer:

$y + 3 = \frac{1}{2}(x-6)$

Step-by-step explanation:

1) First, find the slope of y + 7 = -2 (x - 6). We can see that it's already in point-slope form, or $y-y_1 = m (x-x_1)$ format. Remember that the number in place of the $m$ is the slope. Therefore, -2 is the slope of that equation.

What we need is the slope that is perpendicular to that, though. So, find the opposite reciprocal of -2. To do this, change its sign, convert it into a fraction ( $-\frac{2}{1}$ ), and flip its numerators and denominators. Therefore, the perpendicular slope would be $\frac{1}{2}$ .

2) Now that we have a slope and a point the line passes through, we can write an equation using the point-slope formula, $y-y_1 = m (x-x_1)$ . In order to write an equation, the $x_1$ , $y_1$ , and $m$ have to be substitute for with real values.

The $m$ represents the slope. We already calculated that in the last step, so put $\frac{1}{2}$ in place of the $m$ . The $x_1$ and $y_1$ represent the x and y values of a point the line passes through. We know that the line has to pass through (6, -3), so substitute 6 for $x_1$ and -3 for $y_1$ :

$y - (-3) = \frac{1}{2}(x -(6))\\y + 3 = \frac{1}{2}(x - 6)$

Therefore, (again, assuming that the line can be put in point-slope form) the answer is $y + 3 = \frac{1}{2}(x-6)$ .

5 0

3 years ago