-1 is your answer, if that is what you want...
Answer:
I think it's the first one... but I'm not pretty sure.
Given:
m∠APD = (7x + 1)°
m∠DPC = 90°
m∠CPB = (9x - 7)°
To find:
The measure of arc ACD.
Solution:
<em>Sum of the adjacent angles in a straight line = 180°</em>
m∠APD + m∠DPC + m∠CPB = 180°
7x° + 1° + 90° + 9x° - 7° = 180°
16x° + 84° = 180°
Subtract 84° from both sides.
16x° + 84° - 84° = 180° - 84°
16x° = 96°
Divide by 16° on both sides.
x = 6
m∠APB = 180°
m∠BPD = (9x - 7)° + 90°
= (9(6) - 7)° + 90°
= 47° + 90°
m∠BPD = 137°
m∠APD = m∠APB + m∠BPD
= 180° + 137°
= 317°
<em>The measure of the central angle is congruent to the measure of the intercepted arc.</em>
m(ar ACD) = m∠APD
m(ar ACD) = 317°
The arc measure of ACD is 317°.
<h3>
Answer: Choice A. |w - q|</h3>
Let's say for example that w = 10 and q = 7. This means the distance between these values is w-q = 10-7 = 3. This is the distance between w and q.
Now let's make q larger. If w = 12 and q = 20, then w-q = 12-20 = -8 assuming we subtract in the same order. We use absolute value bars to ensure the result is positive. So instead we say
|w - q| = |12 - 20| = | -8 | = 8
Distance is never negative.
Answer: the golf ball with hit the ground again after 2.75 seconds
Step-by-step explanation:
The movement of the golf ball from the ground follows the equation h(t)=-16t^2+44t,
where t is the time in seconds, and h(t) is the height of the ball at a given time t
By the time the golf ball hit the ground, the height from the ground would be zero. This means that we would equate the quadratic equation to zero. It becomes
-16t^2+44t = 0
Dividing both sides by t
16t^2/t = 44t/t
16t = 44
t = 44/16
t = 2.75
