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HACTEHA [7]
3 years ago
12

enrique y carolina fueron a un día de picnic junto con sus amigos .si calcularon que iban a necesitar 9:2 l de jugo que alcáncen

se a todos ¿Cuántos envases de litro necesitan comprar?
Mathematics
1 answer:
SashulF [63]3 years ago
6 0

Answer:

donde está la leche

Step-by-step explanation:

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I kneed to know what 2/3 - 9/10 is so i can do the rest of my homework
Illusion [34]

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-7/30

Step-by-step explanation:

So you need to make the denominators the same number so that you can just subtract the numerators.

(10) 2/3 - (3) 9/10

 20/30 - 27/30

-7/30

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Find the pattern and use inductive reasoning to predict the next number in the sequence 5,5,10,30,120,…
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afdgdfdf

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7 0
3 years ago
Read 2 more answers
Write an inequality for the given description. The product of -5 and an unknown number increased by 15 is less than or equal to
sesenic [268]

Answer:

-5x +15 ≤ 20

Step-by-step explanation:

7 0
3 years ago
Write an equation of the hyperbola given that the center is at (2, -3), the vertices are at (2, 3) and (2, - 9), and the foci ar
zavuch27 [327]
Check the picture below.

so, the hyperbola looks like so, clearly a = 6 from the traverse axis, and the "c" distance from the center to a focus has to be from -3±c, as aforementioned above, the tell-tale is that part, therefore, we can see that c = 2√(10).

because the hyperbola opens vertically, the fraction with the positive sign will be the one with the "y" in it, like you see it in the picture, so without further adieu,

\bf \textit{hyperbolas, vertical traverse axis }
\\\\
\cfrac{(y- k)^2}{ a^2}-\cfrac{(x- h)^2}{ b^2}=1
\qquad 
\begin{cases}
center\ ( h, k)\\
vertices\ ( h,  k\pm a)\\
c=\textit{distance from}\\
\qquad \textit{center to foci}\\
\qquad \sqrt{ a ^2 + b ^2}\\
asymptotes\quad  y= k\pm \cfrac{a}{b}(x- h)
\end{cases}\\\\
-------------------------------

\bf \begin{cases}
h=2\\
k=-3\\
a=6\\
c=2\sqrt{10}
\end{cases}\implies \cfrac{[y- (-3)]^2}{ 6^2}-\cfrac{(x- 2)^2}{ b^2}=1
\\\\\\
\cfrac{(y+3)^2}{ 36}-\cfrac{(x- 2)^2}{ b^2}=1
\\\\\\
c^2=a^2+b^2\implies (2\sqrt{10})^2=6^2+b^2\implies 2^2(\sqrt{10})^2=36+b^2
\\\\\\
4(10)=36+b^2\implies 40=36+b^2\implies 4=b^2
\\\\\\
\sqrt{4}=b\implies 2=b\\\\
-------------------------------\\\\
\cfrac{(y+3)^2}{ 36}-\cfrac{(x- 2)^2}{ 2^2}=1\implies \cfrac{(y+3)^2}{ 36}-\cfrac{(x- 2)^2}{ 4}=1

3 0
2 years ago
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