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Aleks04 [339]
3 years ago
12

What is the solution to the equation? 36x-20=160

Mathematics
2 answers:
Pepsi [2]3 years ago
8 0
36x - 20 = 160
+ 20 + 20
36x = 180
—— ——
36 36

ANSWER: x = 5
Arisa [49]3 years ago
7 0

Answer:

x=5

Step-by-step explanation:

36x-20=160

first, find the value of x

add 20 from both sides

36x-20=160

+20 +20

36x=180

then, divide 36 from both sides to get x by itself

36x/36=140/36

x=5

now, plug x into the equation to check your work

36(5)-20=160

multiply 36 and 5

180-20=160

subtract 20 from 180

180-20=160

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Step-by-step explanation:

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3 years ago
Which of the following is an extraneous solution of mc015-1.jpg? x = –12 x = –3 x = 3 x = 12
kramer
The answer
the full the question is as follow:
<span>Which of the following is an extraneous solution of (45 - 3x)^1/2 =x -9

for solving such an equation, this is the method:

finding the squared value of each member of the equation
</span>[(45 - 3x)^1/2 ]²  = (x -9)²   (E)
<span>
extend each value of the member
</span>[(45 - 3x)^1/2 ]² = 45 - 3x, because   (sqrt a )² = a
the condition is 45 - 3x≥0 ( because of the square root)
it means  - 3x≥ -45 and  x ≤ 15

(x -9)² = x²-18x + 81
<span>
so </span>45 - 3x = x²-18x + 81, this is equivalent to x² - 15x  +36 =0
<span>
this equation should solve for x, for finding the help

Delta = 15² - 4*36 = 81, so x = - (-15) - sqrt (81)  /  2 *1=15-9 /2= 3

                                      and </span>x = - (-15) +sqrt (81)  /  2 *1= 15 +9/2= 24/2=12
<span>
for x= 12, the equation given above ( equation E) has no solution, because 
we can find 3=9

so </span><span>an extraneous solution is x = 12</span><span>

</span>
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natulia [17]
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