Answer:
1 2/6 is the correct answer
Step-by-step explanation:
in 2 1/6 + -5/6 what you do is you can turn the plus sign into a minus sign and make -5/6 5/6 so now the problem is 2 1/6 - 5/6 and the awnser to that is 1 2/6
Answer:
4.575
Step-by-step explanation:
365.085/79.8=4.575
Roots with imaginary parts always occur in conjugate pairs. Three of the four roots are known and they are all real, which means the fourth root must also be real.
Because we know 3 and -1 (multiplicity 2) are both roots, the last root
is such that we can write

There are a few ways we can go about finding
, but the easiest way would be to consider only the constant term in the expansion of the right hand side. We don't have to actually compute the expansion, because we know by properties of multiplication that the constant term will be
.
Meanwhile, on the left hand side, we see the constant term is supposed to be 9, which means we have

so the missing root is 3.
Other things we could have tried that spring to mind:
- three rounds of division, dividing the quartic polynomial by
, then by
twice, and noting that the remainder upon each division should be 0
- rational root theorem
Answer:
Torrance spends 16$ on his brother
Step-by-step explanation:
You have 100$
So, we have
x (brother) + x (sister) + x (mother) = 100
But, since 10$ less will be spent on the sister than the brother, it becomes (x - 10) and twice + 6$ is spent on the mom, it also becomes (2x + 6)
Our equation then becomes
(x - 10) + x + (2x + 6) = 100
X will end up equaling 26. This is how much is spent on the sister.
(x - 10) will be substituted for (26 - 10), which equals 16.
I'm not sure if this is right so you might want to check with somebody (since I may be wrong) I hope this helps you understand how to basically do it though. <3
Answer:

Step-by-step explanation:
When you use a congruence statement, you must line up the corresponding parts of the triangles.
BC = DE is wrong, because BC = EF.
is correct.
m∠B = m∠F is wrong, because m∠B = m∠E.
AC = EF is wrong, because AC = DF