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Karolina [17]
3 years ago
13

Error Analysis- Charles claimed the function

Mathematics
1 answer:
pogonyaev3 years ago
4 0

Answer:

Answer is below

Step-by-step explanation:

Charles is wrong because 3 doesn't represent exponential decay. This is because 3 is greater than 1, so it represents exponential growth. If the number was less than 1, then it would represent exponential decay.

If this answer is correct, please make me Brainliest!

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(2h³j^-3 k⁴)/3jk<br>Just look at pic​
Troyanec [42]
The answer is: 2•h^3•k^3 / 3•j^4
4 0
2 years ago
Translate this problem to an equation and solve. The area of a patio is 72 square feet. The length of the patio is 1 foot longer
Inessa05 [86]
A = LW
A = 72
L = W + 1

72 = W(W + 1)
72 = W^2 + W
W^2 + W - 72 = 0
(W + 9)(W - 8) = 0

W + 9 = 0
W = -9......extraneous solution...does not work here

W - 8 = 0
W = 8 <==

L = W + 1
L = 8 + 1
L = 9

so the width (W) is 8 ft and the Length is 9 ft
7 0
3 years ago
Micah deposited $4000 between two savings account. One account earns 4% simple interest each year. The other account earns 2% si
N76 [4]

Answer:

Step-by-step explanation:

$3000 * 0.04 = $120

$100 * 0.02 = $20

total 2 accounts = $120 + $20 = $140

answer: $3000 was the originally deposited into the account that pays 4% interest.

6 0
3 years ago
What is the value of x
My name is Ann [436]
X=3



Explanation:

A straight line equals 180°, and they give you the one angle of 56°, so you know 56+ the other equation has to equal 180

56+4x+112=180
168+4x=180

Subtract 168 from both sides

4x=12

Divide 4 from both sides

X=3


You can check by filling it in.


56+4*3+112=

12+56+112=180
5 0
3 years ago
Prove that :( 1 + 1/<img src="https://tex.z-dn.net/?f=tan%5E%7B2%7DA" id="TexFormula1" title="tan^{2}A" alt="tan^{2}A" align="ab
Aliun [14]

Answer:

See explanation

Step-by-step explanation:

Simplify left and right parts separately.

<u>Left part:</u>

\left(1+\dfrac{1}{\tan^2A}\right)\left(1+\dfrac{1}{\cot ^2A}\right)\\ \\=\left(1+\dfrac{1}{\frac{\sin^2A}{\cos^2A}}\right)\left(1+\dfrac{1}{\frac{\cos^2A}{\sin^2A}}\right)\\ \\=\left(1+\dfrac{\cos^2A}{\sin^2A}\right)\left(1+\dfrac{\sin^2A}{\cos^2A}\right)\\ \\=\dfrac{\sin^2A+\cos^2A}{\sin^2A}\cdot \dfrac{\cos^2A+\sin^A}{\cos^2A}\\ \\=\dfrac{1}{\sin^2A}\cdot \dfrac{1}{\cos^2A}\\ \\=\dfrac{1}{\sin^2A\cos^2A}

<u>Right part:</u>

\dfrac{1}{\sin^2A-\sin^4A}\\ \\=\dfrac{1}{\sin^2A(1-\sin^2A)}\\ \\=\dfrac{1}{\sin^2A\cos^2A}

Since simplified left and right parts are the same, then the equality is true.

3 0
3 years ago
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