Recursive
formula is one way of solving an arithmetic sequence. It contains the initial
term of a sequence and the implementing rule that serve as a pattern in finding
the next terms. In the
problem given, the 6th term is provided, therefore we can solve for the initial
term in reverse. To make use of it, instead of multiplying 1.025, we should divide it after
deducting 50 (which supposedly is added).
<span>
Therefore, we perform the given formula: A (n) = <span>1.025(an-1) +
50
</span></span>a(5) =1.025 (235.62) + 50 = 291.51
a(4) = 1.025 (181.09) + 50 = 235.62
a(3) = 1.025 (127.89) + 50 = 181.09
a(2) = 1.025 (75.99) + 50 = 127.89
a(1) = 1.025 (25.36) + 50 = 75.99
a(n) = 25.36
The terms before a(6) are indicated above, since a(6) is already given.
So, the correct answer is <span>
A. $25.36, $75.99.</span>
Plot a graph of y-axis against x-axis.
The graph should be a straight line passing through:
(-2,0.8) , (-1,-0.4) , (0,0) , (1,0.4) and (2,0.8)
Answer:
LEts start with 10^1
If we have positive exponent then we add zeros
10^1= 10
(Put 2 zeros because exponent is 2)
(Put 3 zeros because exponent is 3)
(Put 4 zeros because exponent is 4)
(Put 5 zeros because exponent is 5)
For negative exponent , we make a fraction . we put 1 at the top always and number as the bottom
(Put 1 zero at the bottom because exponent is -1)
(Put 2 zeros at the bottom because exponent is -2)
(Put 3 zeros at the bottom because exponent is -3)
Answer:
100
Step-by-step explanation:
We have the sum of first n terms of an AP,
Sn = n/2 [2a+(n−1)d]
Given,
36= 6/2 [2a+(6−1)d]
12=2a+5d ---------(1)
256= 16/2 [2a+(16−1)d]
32=2a+15d ---------(2)
Subtracting, (1) from (2)
32−12=2a+15d−(2a+5d)
20=10d ⟹d=2
Substituting for d in (1),
12=2a+5(2)=2(a+5)
6=a+5 ⟹a=1
∴ The sum of first 10 terms of an AP,
S10 = 10/2 [2(1)+(10−1)2]
S10 =5[2+18]
S10 =100
This is the sum of the first 10 terms.
Hope it will help.
<span>You can get those ordered pairs subtracting 9-0.5, then that result minus 0.5 because from the rate the candle reduces its height 0.5inches per each hour.Part B: Is this relation a function? Yes, because each value of x has a single result or output in “y” (image)Part C: Yes, only difference is the time, the candle reduces its height 0.45 inches per each hour, examples of ordered pairs: (0,9) (1,8.55) (2,8.1)</span>
