Average=(total number)/(number of items)
given that the final exam counts as two test, let the final exam be x. The weight of the final exams on the average is 2, thus the final exam can be written as 2x because any score Shureka gets will be doubled before the averaging.
Hence our inequality will be as follows:
(67+68+76+63+2x)/6≥71
(274+2x)/6≥71
solving the above we get:
274+2x≥71×6
274+2x≥426
2x≥426-274
2x≥152
x≥76
b] The above answer is x≥76, the mean of this is that if Shureka is aiming at getting an average of 71 or above, then she should be able to get a minimum score of 76 or above. Anything less than 76 will drop her average lower than 71.
Answer: length = 28 meters
Width = 15 meters
Step-by-step explanation:
Let L represent the length of the rectangular garden.
Let W represent the width of the rectangular garden.
The formula for determining the perimeter of a rectangle is expressed as
Perimeter = 2(L + W)
The rectangular garden is enclosed with eighty-six meters of fencing. This means that
2(L + W) = 86
Dividing through by 2, it becomes
L + W = 43- - - - - - - - - - - -1
The garden is thirteen meters longer than it is wide.. This means that
L = W + 13
Substituting L = W + 13 into equation 1, it becomes
W + 13 + W = 43
2W + 13 = 44
2W = 43 - 13
2W = 30
W = 30/2
W = 15
L = W + 13 = 15 + 13
L = 28
Step-by-step explanation:
if I understand this correctly than you are looking for the inverse function of f(x) = y = 3x³.
the inverse function simply tries to calculate the original x it of the original y.
and then, to make it a formal function, we rename x to y and y to x.
y = 3x³
x³ = y/3
![x = \sqrt[3]{ \frac{y}{3} }](https://tex.z-dn.net/?f=x%20%3D%20%20%5Csqrt%5B3%5D%7B%20%5Cfrac%7By%7D%7B3%7D%20%7D%20)
=> as "regular" function
![y = {f}^{ - 1} (x)= \sqrt[3]{ \frac{x}{3} }](https://tex.z-dn.net/?f=y%20%20%3D%20%20%7Bf%7D%5E%7B%20-%201%7D%20%28x%29%3D%20%20%5Csqrt%5B3%5D%7B%20%5Cfrac%7Bx%7D%7B3%7D%20%7D%20)
Answer:
$3,550 dollars
Step-by-step explanation:
6.4% off savings
- a total of $2,400
Answer:
0.375 is answer
Step-by-step explanation:
Given that the math teacher gave her students two tests. On the first test, 80% of the class passed the test. But only 30% of the class passed both tests.
Let A - the students pass I test
B = students pass second test
Then P(A) = 80%=0.8 and P(AB) = 30% =0.30
Required probability =probability that a student passes the second test, given that they passed the first one
= P(B/A) = P(AB)/P(A)
= 0.30/0.80
=3/8
=0.375
Right answer is 0.375
