Find the the first two steps necessary to simplify 16+4(3+8)2-21

Does Anyone know this?

lukranit [14]

Answer:

∠AEC = 139°

Step-by-step explanation:

Since EC bisects ∠BED then ∠BEC = ∠CED = 4x + 1

∠AED = ∠AEB + ∠BEC + ∠CED = 180 ← straight angle

Substitute values into the equation

11x - 12 + 4x + 1 + 4x + 1 = 180, that is

19x - 10 = 180 ( add 10 to both sides )

19x = 190 ( divide both sides by 19 )

x = 10

Hence

∠AEC = ∠AEB + ∠BEC = 11x - 12 + 4x + 1 = 15x - 11, hence

∠AEC = (15 × 10) - 11 = 150 - 11 = 139°

6 0

3 years ago

The cat is a high speed catamaran auto ferry that operates between city A and city B the cat can make the trip in about 2 and 1/

Lyrx [107]

If the CAT operates with a constant speed of 53 mph (which means it beats 53 miles in one hour) and makes a trip in about 2 and 1/2 hours, we just have to multiply 53 by 2 1/2 to find out the overall distance it's beating in that time:

53 * 2 1/2 =
= 53 * 2.5 =
= 132.5

Answer: City A is about <u>132.5 miles</u> from city B.

4 0

3 years ago

Travis spends $2 in 10 pieces of gum to share with his friends. What is the correct unit rate?

DIA [1.3K]

Answer:

1 piece of gum= 20 cents

7 0

3 years ago

Consider testing H^0: u=20 against H^a: u<20 where u is the mean number of latex gloves used per week by all hospital employe

iragen [17]

Answer:

Part a: P-value

The first step is calculate the degrees of freedom, on this case:

$df=n-1=46-1=45$

Since is a one sided test the p value would be:

$p_v =P(t_{(45)}$

Part b: Conclusion

If we compare the p value and the significance level given $\alpha=0.01$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to fail reject the null hypothesis, and we can conclude that the true mean is not lower than 20 at 1% of signficance.

a. There is insufficient evidence to reject h^0

Step-by-step explanation:

Data given and notation

$\bar X=19.1$ represent the sample mean

$s=11.8$ represent the sample standard deviation

$n=46$ sample size

$\mu_o =20$ represent the value that we want to test

$\alpha=0.01$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the mean is lower than 20, the system of hypothesis would be:

Null hypothesis: $\mu \geq 20$

Alternative hypothesis: $\mu < 20$

If we analyze the size for the sample is > 30 but we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

Calculate the statistic

We can replace in formula (1) the info given like this:

$t=\frac{19.1-20}{\frac{11.8}{\sqrt{46}}}=-0.517$

Part a: P-value

The first step is calculate the degrees of freedom, on this case:

$df=n-1=46-1=45$

Since is a one sided test the p value would be:

$p_v =P(t_{(45)}$

Part b: Conclusion

If we compare the p value and the significance level given $\alpha=0.01$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to fail reject the null hypothesis, and we can conclude that the true mean is not lower than 20 at 1% of signficance.

a. There is insufficient evidence to reject h^0

5 0

3 years ago

I can't seem to find the answer for this I'm pretty sure it's non linear

Nata [24]

Answer:

(d) No. Slope is not constant.

Step-by-step explanation:

You want to know if the given graph shows a linear function.

<h3>Linear function</h3>

The graph of a linear function is a straight line. The points on the graph shown do not form a straight line, so the function is nonlinear.

<h3>Rate of change</h3>

The rate of change of a function is the ratio of "rise" to "run" between two points in the graph. This ratio is also called the "slope." For a straight line, the rate of change (slope) is constant. That is, a linear function has a constant rate of change.

If the function is nonlinear, its rate of change is not constant. The converse is also true: if the slope is not constant, the function is nonlinear.

6 0

1 year ago