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enot [183]
3 years ago
13

What does zero represent in your story problem?

Mathematics
2 answers:
Alex777 [14]3 years ago
8 0

Answer:

they would be 10 feet apart and I'm not sure about the representation of 0

diamong [38]3 years ago
3 0

Answer:

0 is sea level

Step-by-step explanation:

You might be interested in
3(x – 9)2 + 15 = 195<br> Solving quadratics with square root
hoa [83]

Answer:

x -  \frac{6 -  \sqrt{80} }{2}  = 3 - \sqrt[2]{5} = 1.472 \\ x -  \frac{6 +  \sqrt{80} }{2}  = 3 -  \sqrt[2]{5} = 7.472

Step-by-step explanation:

Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :

{(3x - 9)}^{2} \ + 15 - (195) = 0  

Step 1 :Evaluate :  (3x-9)2   =  9x^2-54x+81   =   3 • (3x^2 - 18x - 43)    

Step 2: Pull out like factors :

{9x}^{2} - 54x - 99 = 9•( {x}^{2} - 6x - 11)

Step 3: Trying to factor by splitting the middle term

   Factoring   {x}^{2} - 6x - 11

The first term is,  {x}^{2}  its coefficient is  1 .

The middle term is,  { - 6x} its coefficient is -6 .

The last term, "the constant", is - 11

 Step 4: Multiply the coefficient of the first term by the constant  

1 \: • -11 = -11

Step-5 : Find two factors of -11  whose sum equals the coefficient of the middle term, which is -6. 

- 11 + 1 =  - 10 \\  - 1 + 11 = 10

9 • ( {x}^{2}  - 6x - 11)  = 0

Step 6: 

  Solve :   

9 = 0

This equation has no solution.

A a non-zero constant never equals zero.

Find the Vertex of y =  {x}^{2} -6x-11

Parabolas have a highest or a lowest point called the Vertex .   Our parabola opens up and accordingly has a lowest point (AKA absolute minimum) .   We know this even before plotting  "y"  because the coefficient of the first term, 1 , is positive (greater than zero). 

 Each parabola has a vertical line of symmetry that passes through its vertex. Because of this symmetry, the line of symmetry would, for example, pass through the midpoint of the two  x -intercepts (roots or solutions) of the parabola. That is, if the parabola has indeed two real solutions. 

 Parabolas can model many real life situations, such as the height above ground, of an object thrown upward, after some period of time. The vertex of the parabola can provide us with information, such as the maximum height that object, thrown upwards, can reach. For this reason we want to be able to find the coordinates of the vertex. 

 For any parabola,A{x}^{2}+Bx+C,the  x -coordinate of the vertex is given by  -B/(2A) . In our case the x

coordinate is  3.0000 

Plugging into the parabola formula   3.0000  for  x  we can calculate the  

y -coordinate :   y = 1.0 * 3.00 * 3.00 - 6.0 * 3.00 - 11.0 or   y

= -20.000

Root plot for y =  {x}^{2} - 6x - 11

Axis of Symmetry (dashed)  {x}={ 3.00} 

Vertex at  {x,y} = { 3.00,-20.00} 

 x -Intercepts (Roots) :

Root 1 at  {x,y} = {-1.47, 0.00} 

Root 2 at  {x,y} = { 7.47, 0.00}

(Please click above graph)

Solve

{x}^{2} \times - 6x = 11

 by Completing The Square .

 Add  11  to both side of the equation :

  {x}^{2} -6x = 11

Now the clever bit: Take the coefficient of  x , which is  6 , divide by two, giving  3 , and finally square it giving  9 

Add  9  to both sides of the equation :

  On the right hand side we have :

   11  +  9    or,  (11/1)+(9/1) 

  The common denominator of the two fractions is  1   Adding  (11/1)+(9/1)  gives  20/1 

  So adding to both sides we finally get :

   x2-6x+9 = 20

Adding  9  has completed the left hand side into a perfect square :

{x}^{2} - 6x + 9 \\ (x - 3) • (x - 3)  \\  {(x - 3)}^{2}

Things which are equal to the same thing are also equal to one another. Since

{x}^{2} - 6x + 9 = 20 \: and \:  {x}^{2} - 6x + 9 =  {(x - 3)}^{2}

then, according to the law of transitivity,

  

The Square Root Principle says that When two things are equal, their square roots are equal.

Note that the square root of

= (x - 3)^{2}  \:is \:  \\  = {(x - 3)}^{ \frac{2}{2}}  \\ =   {(x - 3)}^{1}  \\  = (x - 3)

Now, applying the Square Root Principle to  Eq. #3.3.1  we get:

x - 3 =  \sqrt{20}

Add  3  to both sides to obtain:

  

x = 3 +  \sqrt{20}

Since a square root has two values, one positive and the other negative

{x}^{2} - 6x - 11 = 0

   has two solutions:

x = 3 +  \sqrt{20}  \\  or \: x  = 3 -  \sqrt{20}

Solving   

{x}^{2} - 6x - 11

by the Quadratic Formula .

 According to the Quadratic Formula,  x  , the solution for   Ax2+Bx+C  = 0  A{x}^{2}+Bx+C= 0, where  A, B  and  C  are numbers, often called coefficients, is given by :

x  =  \frac{ - B± \sqrt{ {B}^{2 - 4AC} } }{2A}

In our case,  A   =     1

                      B   =    -6

                      C   =  -11

Accordingly,  B2  -  4AC   

 = 36 - (-44)

               =  80

Applying the quadratic formula :

x =  \frac{6± \sqrt{80} }{2}

Can  \sqrt{80}

be simplified ?

Yes! The prime factorization of  80   is

   2•2•2•2•5 

To be able to remove something from under the radical, there have to be  2  instances of it (because we are taking a square i.e. second root).

√ 80   =  √ 2•2•2•2•5  

 = 2•2•√ 5 

           = ±  4 • √ 5

\sqrt{80}  =  \sqrt{2•2•2•2•5}  \\ =  \sqrt[2•2•]{5}  \\    = \sqrt[± 4•]{5}

\sqrt{5} rounded to 4 decimal digits, is   2.2361

 So now we are looking at:

           x  =  ( 6 ± 4 •  2.236 ) / 2

x  = \frac{  (6 ± 4 •  2.236)}{2}

Two real solutions:

x = \frac{(6+√80)}{2} =3+2 \sqrt{5} = 7.472     or   x = \frac{6 -  \sqrt{80} }{2} =3-2\sqrt{5}  = -1.472

6 0
3 years ago
A magazine sales person earns $250 a week plus a commission of of the total sales. If the total sales for the week were $693, wh
UNO [17]
It would be 346 with a remainder of 1 and if this is wrong, I divided
8 0
3 years ago
Simplify. (Note: x ≠ 0)
mihalych1998 [28]
I think the answer is D! Hope This Helps!
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Read 2 more answers
Is the following relation a function? {(3, 2), (3, −2), (1, −4), (−1, 2)}
Ksivusya [100]

Step-by-step explanation:

no it is not because if 3 maps on 2, then it cannot map on -2 at the same time

8 0
3 years ago
A track coach is trying to improve the 50 -meter-dash times of the track team. He times each student and then implements a month
Aleks04 [339]

Answer:

-5

Step-by-step explanation:

Given the two box plots showing the number of seconds the students completes the 50-meter-dash race before and after the program, we are to determine the difference between the median value of seconds before and after the program.

Median in a box plot is represented by the vertical line that divides the rectangular box in a box plot.

Thus, the median before the program = 15 seconds

The Median after the program = 10 seconds

The median change = 10 - 15 = -5 seconds.

This means, after the program, most of the students now finish the 50-meter-dash faster, about 5 seconds less the former seconds used before the program.

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3 years ago
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