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2 years ago

What is 63 percent of 69

Mathematics

2 answers:

belka [17]2 years ago

8 0

Answer:43.47

Step-by-step explanation: you have to mulitply 63 and 69 and you will get 43.47

irina [24]2 years ago

7 0

Description

To calculate a percent of a number you must find the total amount or the whole number.

After that Divide the number that you wish to determine the percentage for

Then multiply the value from step two by 100.

In this case the answer will be 43.47

64 percent of 69 = 43.47

Answer: 43.47

Hope this helps

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It takes Bert 30 minutes longer to mow a rectangular lawn that measures 30 feet by 25 feet than it takes him to mow a rectangula

nevsk [136]

Answer:

C: 70 Mins

Step-by-step explanation:

1, 20ft*15ft=300ft^2

2, 30ft*25ft=750ft^2

3, 750ft-350ft=450ft^2

4, 450 ft^2 = 30 mins

5, 350ft=750ft=1050ft^2

6, 1050/450=2.3333

7, 30*2.3333=70

8, 70 mins

4 0

2 years ago

1=1/8+x+2/8 Pls help and hurry

TEA [102]

Answer:

x = 5/8 plz give branliest

Step-by-step explanation:

Using the equation, $1 = \frac{1}{8} + x + \frac{2}{8}$

simplify 1 = x + $\frac{3}{8}$

1 - $\frac{3}{8}$ = x

$\frac{5}{8}$ = x

6 0

3 years ago

Read 2 more answers

Sunspots have been observed for many centuries. Records of sunspots from ancient Persian and Chinese astronomers go back thousan

Lunna [17]

Answer:

(a) Null Hypothesis, $H_0$ : $\mu$ $\leq$ 41

Alternate Hypothesis, $H_A$ : $\mu$ > 41

(b) The value of z test statistics is 1.08.

(c) We conclude that the mean sunspot activity during the Spanish colonial period was lesser than or equal to 41.

Step-by-step explanation:

We are given that in a random sample of 40 such periods from Spanish colonial times, the sample mean is x¯ = 47.0. Previous studies of sunspot activity during this period indicate that σ = 35.

It is thought that for thousands of years, the mean number of sunspots per 4-week period was about µ = 41.

Let $\mu$ = mean sunspot activity during the Spanish colonial period.

(a) Null Hypothesis, $H_0$ : $\mu$ $\leq$ 41 {means that the mean sunspot activity during the Spanish colonial period was lesser than or equal to 41}

Alternate Hypothesis, $H_A$ : $\mu$ > 41 {means that the mean sunspot activity during the Spanish colonial period was higher than 41}

The test statistics that would be used here One-sample z test statistics as we know about the population standard deviation;

T.S. = $\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

where, $\bar X$ = sample mean = 47

σ = population standard deviation = 35

n = sample of periods from Spanish colonial times = 40

So, the test statistics = $\frac{47-41}{\frac{35}{\sqrt{40} } }$

= 1.08

(b) The value of z test statistics is 1.08.

(c) Now, the P-value of the test statistics is given by;

P-value = P(Z > 1.08) = 1 - P(Z < 1.08)

= 1 - 0.8599 = 0.1401

Since, the P-value of the test statistics is higher than the level of significance as 0.1401 > 0.05, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which we fail to reject our null hypothesis.

Therefore, we conclude that the mean sunspot activity during the Spanish colonial period was lesser than or equal to 41.

8 0

3 years ago

Use the table below to answer this question:

In-s [12.5K]

In the interval from x=-1 to x=2, x increases by 3. In that same interval, y increases by 6 from -3 to +3. The average rate of change is
.. average rate of change = (increase in y)/(increase in x) = 6/3 = 2

The average rate of change is 2 over the given interval.

8 0

3 years ago

Evaluate |x|+(-2x^2) for x=3 Answers -9 -15 21

Nikolay [14]

Hello from MrBillDoesMath!

Answer:

-15

Discussion:

We are asked to evaulate:

abs(3) + ( -2 (3)^2) = => as abs(3) = 3

3 + (-2*9) =

3 - 18 =

-15

Thank you,

MrB

8 0

2 years ago