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3 years ago

Is someone’s opinion a statistical question???? Pls help

Mathematics

1 answer:

Volgvan3 years ago

6 0

Answer:

Step-by-step explanation:

A statistical question is a question that can be answered by collecting data that vary. For example, “How old am I?” is not a statistical question, but “How old are the students in my school?” is a statistical question.

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Amy reached into a bag, recorded the color of the tile she picked, returned the tile and drew again. These are the tiles she has

Vedmedyk [2.9K]

Answer:

(a) P(next ball with blue) = $\frac{3}{10}$ (b) P(Not to be red) = $1-\frac{2}{5} =\frac{3}{5}$

(c) P(drawing 70 times yellow ball) = $\frac{1}{10} \times 70 = 7$ .

Step-by-step explanation:

Given that,

The total outcomes of the color of tile are :-

Red , Red, Blue, Yellow, Blue, Red, Green, Red, Blue, Green.

From the Question,

Total number of outcomes = 10

(a) What is the probability that her next draw will be blue ?

Red = 4,

Blue = 3,

Green = 2,

Yellow = 1.

P(next ball with blue) = $\frac{3}{10}$ .

(b) What is the probability that her next draw will NOT be red?

P(Red ball) = $\frac{4}{10} = \frac{2}{5}$

But we have to find

P(Not to be red) = $1-\frac{2}{5} =\frac{3}{5}$

(c) If Amy draws 70 more times with the same tiles from the question above, what probability would you expect a yellow?

P(Yellow ball) = $\frac{1}{10}$

drawing it 70 times we get the probability

P(drawing 70 times yellow ball) = $\frac{1}{10} \times 70 = 7$ .

5 0

3 years ago

Karla rode her bicycle 135 miles in 9 weeks, riding the same distance each week. Brad rode his bicycle 102 miles in 6 weeks, rid

blsea [12.9K]

Answer:

Karla's 15 miles per week to Brad's 17 miles per week.

Step-by-step explanation:

First, we would need find the total number of miles each individual rides per week. We do this by dividing the total miles ridden by the number of weeks it took for each individual like so...

Karla: 135 / 9 = 15 miles per week

Brad: 102 / 6 = 17 miles per week

Finally, the comparison would be

Karla's 15 miles per week to Brad's 17 miles per week.

8 0

3 years ago

What is the sum of x + 9?

vovikov84 [41]

So 30/48=15/(x+9)
this could be easily solved by recognizing the proportion (the other way is usiing full algebra and doing multiply both sides by 48(x+9) and then divide both sides by 30 then subtract 9)
30 is 2 times of 15
therefor 48 is 2 times of (x+9)
48=2 times (x+9)
divide both sides by 2
24=x+9
subtract 9
15=x

x=15

5 0

3 years ago

Liberty solved the following equation 3 + 2x

frutty [35]

Where is the rest of the question

6 0

3 years ago

Read 2 more answers

Help me? idk the answer :P

Alexus [3.1K]

$\bf \left.\qquad \qquad \right.\textit{negative exponents}\\\\
a^{-{ n}} \implies \cfrac{1}{a^{ n}}
\qquad \qquad
\cfrac{1}{a^{ n}}\implies a^{-{ n}}
\qquad \qquad 
a^{{{ n}}}\implies \cfrac{1}{a^{-{{ n}}}}\\\\
-------------------------------\\\\
\left( 2^8\cdot 3^{-5}\cdot 6^0 \right)^{-2}\left( \cfrac{3^{-2}}{2^3} \right)^4\cdot 2^{28}\impliedby \textit{let's do the first group}
\\\\
-------------------------------\\\\
$

$\bf \left( 2^8\cdot \cfrac{1}{3^5}\cdot 1 \right)^{-2}\implies \left( \cfrac{2^8}{3^5} \right)^{-2}\implies \left( \cfrac{3^5}{2^8} \right)^{2}\implies \cfrac{3^{2\cdot 5}}{2^{2\cdot 8}}\implies \boxed{\cfrac{3^{10}}{2^{16}}}\\\\
-------------------------------\\\\
\textit{now the second group}\qquad \left( \cfrac{3^{-2}}{2^3} \right)^4\implies \left( \cfrac{\frac{1}{3^2}}{2^3} \right)^4\implies \left( \cfrac{1}{2^3\cdot 3^2} \right)^4$

$\bf \cfrac{1^4}{2^{4\cdot 3}\cdot 3^{4\cdot 2}}\implies \boxed{\cfrac{1}{2^{12}\cdot 3^8}}\\\\
-------------------------------\\\\
\textit{so we end up with\qquad }\cfrac{3^{10}}{2^{16}}\cdot \cfrac{1}{2^{12}\cdot 3^8}\cdot 2^{28}\implies \cfrac{3^{10}\cdot 2^{28}}{2^{16}\cdot 2^{12}\cdot 3^8}
\\\\\\
\cfrac{3^{10}\cdot 2^{28}}{2^{16+12}\cdot 3^8}\implies \cfrac{3^{10}\cdot 2^{28}}{2^{28}\cdot 3^8}\implies 3^{10}\cdot 2^{28}\cdot 2^{-28}\cdot 3^{-8}$

$\bf 3^{10-8}\cdot 2^{28-28}\implies 3^2\cdot 1\implies 3^2\implies 9$

7 0

3 years ago