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3 years ago

14

In an equation of the form k = ax^2 + bx + c with a > 0, the least possible value of k occurs at x = -b/(2a). In the equation

k = (6x + 12)(x - 8), what is the least possible value for k?

1 answer:

Lynna [10]3 years ago

5 0

Answer:

$k= 6x^{2} -36x-96$

Is what I got in a calculator but however, if you'd try and solve for K you won't get a complete answer.

Hope this helped :)

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4 years ago

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3 years ago

a person invest in 9000 in a bank. the bank pays 5% interest compounded semi annually. to the nearest tenth of a year, how long

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10.1 years.

Step-by-step explanation:

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No. of times interest compounded = 2 times in an year

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The formula for amount:

$A=P(1+\frac{r}{n})^{nt}$

where, P is principal, r is rate of interest, n is no. of times interest compounded in an year and t is time in years.

Substitute the given values in the above formula.

$14800=9000(1+\frac{0.05}{2})^{2t}$

$\frac{14800}{9000}=(1+0.025)^{2t}$

$1.644=(1.025)^{2t}$

Taking log both sides.

$\log(1.644)=\log(1.025)^{2t}$

$\log(1.644)=2t\log(1.025)$ $[\because \log a^b=b\log a]$

$\frac{\log(1.644)}{2\log(1.025)}=t$

$t=10.066$

$t=10.1$

Therefore, the required time is 10.1 years.

3 0

3 years ago