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3 years ago

How many moles of water will be produced if the reaction begins with 9.50 mol NH3?

Chemistry

1 answer:

gogolik [260]3 years ago

8 0

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3 years ago

Hydrogen peroxide can act as either an oxidizing agent or a reducing agent depending on the species present in solution. Write t

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Reduction: 2 H⁺(aq) + H₂O₂(aq) + 2 e⁻ ⇒ 2 H₂O(l)

Oxidation: H₂O₂(aq) ⇒ O₂(g) + 2 H⁺(aq) + 2 e⁻

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2 H⁺(aq) + H₂O₂(aq) + 2 e⁻ ⇒ 2 H₂O(l)

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3 years ago

A solution is prepared by dissolving 318.6 g sucrose (C12H22O11) in 4905 g of water. Determine the molarity of the solution

alexandr1967 [171]

The molarity of sucrose solution is 0.19 M.

The molarity of HCl is 12.8 M.

<u>Explanation:</u>

a. Molarity can be found by finding its moles and volume of water in L and then dividing both(moles divided by volume in Litres).

Mass of sucrose = 318. 6 g

Molar mass of sucrose = 342.3 g/mol

Moles = $$\frac{mass}{molar mass}$

= $$\frac{318.6 g}{342.3 g/mol}$

= 0.93 moles

Mass of water = 4905 g

Density of water = 1000 g/L

Volume = $$\frac{mass}{density}$

= $$\frac{4905 g }{1000 g/L}$

= 4.905 L

Now we can find the molarity = $$\frac{moles}{Volume(L)}$

= $$\frac{0.93 moles}{4.905 L}$

= 0.19 M

So the molarity of sucrose solution is 0.19 M.

b. The molarity of HCl can be found as follows.

It is given that 39% HCl that means it contains 39 g of acid in 100 g of water.

Density of the solution is 1.20 g/mL, from this mass can be found as,

$$\frac{1 L \times 1000 mL \times 1.20 g}{1 L \times 1 mL}$

= 1200 g

Now we have to find out the amount of HCl in grams as,

$$\frac{1200g \times 39 g HCl }{100 g solution}$

= 468 g HCl

Now we have to find the number of moles,

moles = $$\frac{468 g}{36.46 g/mol}$

= 12.8 moles

Molarity of HCl = $$\frac{12.8 moles}{1 L }$

= 12.8 M

So the molarity of HCl is 12.8 M.

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3 years ago