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sweet [91]
3 years ago
14

Hydrogen peroxide can act as either an oxidizing agent or a reducing agent depending on the species present in solution. Write t

he balanced half-reaction equations for each situation. Write the balanced half-reaction equation for when H2O2(aq) acts as an oxidizing agent in an acidic solution. Phases are optional.
Chemistry
1 answer:
Gekata [30.6K]3 years ago
3 0

Answer:

Reduction: 2 H⁺(aq) + H₂O₂(aq) + 2 e⁻ ⇒ 2 H₂O(l)

Oxidation: H₂O₂(aq) ⇒ O₂(g) + 2 H⁺(aq) + 2 e⁻

Explanation:

In H₂O₂, hydrogen has the oxidation number +1 and oxygen the oxidation number -1.

In the reduction half-reaction (H₂O₂ is the oxidizing agent), H₂O₂ forms H₂O. The oxidation number of oxygen decreases from -1 to -2.

2 H⁺(aq) + H₂O₂(aq) + 2 e⁻ ⇒ 2 H₂O(l)

In the oxidation half-reduction (H₂O₂ is the reducing agent), H₂O₂ forms O₂. The oxidation number of oxygen increases  from -1 to 0.

H₂O₂(aq) ⇒ O₂(g) + 2 H⁺(aq) + 2 e⁻

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If you performed a combustion reaction of 2-ethyl, 4-methylpropene, what products would you expect to be present?
Dafna1 [17]

The question is incomplete, here is the complete question:

If you performed a combustion reaction of 2-ethyl-1-methylpropene, what products would you expect to be present?

Answer: The products of the combustion of 2-ethyl-1-methylpropene are carbon dioxide and water.

<u>Explanation:</u>

Combustion reaction is defined as the reaction in which a hydrocarbon reacts with oxygen gas to produce carbon dioxide gas and water molecule.

\text{Hydrocarbon}+O_2\rightarrow CO_2+H_2O

We are given a chemical compound, which is 2-ethyl-1-methylpropene. The chemical formula of this compound is C_6H_{13}

The chemical equation for the combustion of 2-ethyl-1-methylpropene follows:

4C_6H_{13}+37O_2\rightarrow 24CO_2+26H_2O

By Stoichiometry of the reaction:

4 moles of 2-ethyl-1-methylpropene reacts with 37 moles of oxygen gas to produce 24 moles of carbon dioxide and 26 moles of water

Hence, the products of the combustion of 2-ethyl-1-methylpropene are carbon dioxide and water.

6 0
4 years ago
A substance has a freezing point of 24 °C. Which of the following is true for the substance?
inn [45]

Answer:

It will also change from a solid to a liquid at 24°C while the solid gains energy.

Explanation:

Freezing point is the temperature at which a solid and liquid co-exist.

In other words,it is the temperature at which a solid gains energy to overcome the force of attraction between molecules to become liquid or a liquid looses energy to become a solid.

Hence at 24°C:

  • The substance changes from solid to liquid by gaining energy
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Now let us check the options:

The last two options are wrong since conversion is not between solid and gas.It is between solid and liquid.

The first option is wrong as solid gains energy to become liquid.

Hence the correct answer is second option.

4 0
4 years ago
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Answer:

Hey!

After the slight confusion (haha)...

Your answer should be a CHEMICAL CHANGE / PROPERTY

Explanation:

Its CHEMICAL because the sodium has reacted with the air (oxygen in technical terms) which then forms SODIUM OXIDE...the tarnishing of the cut sodium surface it a thin layer of the SODIUM OXIDE...

HOPE THIS HELPED!

6 0
3 years ago
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Answer:

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