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WITCHER [35]
3 years ago
6

An asset falling under the MACRS five-year class was purchased three years ago for $200,000 (its original depreciation basis). C

alculate the cash flows if the asset is sold now at a) $60,000 and b) $80,000. Assume the applicable tax rate is 40 percent.
Business
1 answer:
Nitella [24]3 years ago
3 0

Answer:

(a) The cash flows is $59,040.

(b) The cash flows is $71,040.

Explanation:

From the  Modified Accelerated Cost Recovery System (MACRS) Tables, the depreciation rates for the first 3 years for an asset falling under the MACRS five-year class are 20%, 32% and 19.2%. Therefore, we have:

Accumulated depreciation rate = 20% + 32% + 19.2% = 71.20%

Accumulated depreciation = Cost of the asset * Accumulated depreciation rate =  $200,000 * 71.20% = $142,400

Net book value of the asset = Cost of the asset - Accumulated depreciation = $200,000 - $142,400 = $57,600

We can now proceed as follows:

(a) Calculate the cash flows if the asset is sold now at $60,000

Capital gains = Sales proceeds - Net book value = $60,000 - $57,600 = $2,400

Capital gains tax = Capital gains * Tax rate = $2,400 * 40% = $960

Net sales proceeds = Sales proceeds - Capital gains tax = $60,000 - $960 = $59,040

Therefore, the cash flows is $59,040 net sales proceeds.

(b) Calculate the cash flows if the asset is sold now at $80,000

Capital gains = Sales proceeds - Net book value = $80,000 - $57,600 = $22,400

Capital gains tax = Capital gains * Tax rate = $22,400 * 40% = $8,960

Net sales proceeds = Sales proceeds - Capital gains tax = $80,000 - $8,960 = $71,040

Therefore, the cash flows is $71,040 net sales proceeds.

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If a bank holds $450,000 in required reserves, and $1.8 million in total deposits, then the deposit expansion multiplier is:____
timofeeve [1]

Answer:

4

Explanation:

A bank holds 450,000 in required reserves

The bank also hold 1,800,000 in total deposits

Therefore the deposits expansion multiplier can be calculated as follows

= 1,800,000/450,000

= 4

Hence the deposits expansion multiplier is 4

7 0
2 years ago
Studies on a machine that molds plastic water pipe indicate that when it is injecting 1-inch diameter pipe, the process standard
Otrada [13]

Answer:

b. 0.67

Explanation:

UCL = 1 + 0.10

        = 1.10 inch

LCL = 1 - 0.10

       = 0.9 inch

standard deviation = 0.005 inch

mean = 1 inch

Cpk

= min[(UCL - mean)/(3*standard deviation) , (mean - LCL)/(3*standard deviation))]

= min[(1.10 - 1)/(3*0.05) , (1 - 0.9)/(3*0.05))]

= min[0.67 , 0.67]

= 0.67

Therefore, Theprocess capability index (Cpk) if the long-run process mean is 1 inch is 0.67

3 0
3 years ago
An automobile battery manufacturer offers a 39/50 warranty on its batteries. The first number in the warranty code is the free-r
balandron [24]

Answer:

1)

If the manufacturer's assumptions are correct, it would need to replace 8.23% of its batteries free of charge.

Option a) 8.23% is the correct option

2)

the required standard deviation is 3.8

Option a) 3.8 is the correct answer

Explanation:

Given the data in the question;

mean μ = 44

standard deviation σ = 3.6

if a battery fails within 39 months of purchase, the manufacturer replaces the battery at no charge to the consumer. If the battery fails after 39 months but within 50 months

1)

If the manufacturer's assumptions are correct, it would need to replace_____ of its batteries free of charge

p( X < 39 ) = P( X-μ/σ < 39-μ/σ )

we substitute

= p( Z < ((39-44)/3.6 ))

= p( Z < -1.39 )

from standard normal table; p( Z < -1.39 ) = 0.08226 ≈ 0.0823

p( X < 39 ) = 0.0823 or 8.23%

Therefore, If the manufacturer's assumptions are correct, it would need to replace 8.23% of its batteries free of charge.

Option a) 8.23% is the correct option

2)

The company finds that it s replacing 9.34% of its batteries free of charge. It suspects that its assumption about the standard deviation of the life of its batteries is incorrect. A standard deviation of ______ results in a 9.34% replacement rate.

given that;

P( Z < x-μ/σ ) = 9.34%

⇒ P( Z < 39-44/σ ) = 0.0934 ----- let this be equation 1

now, from standard normal tables

∅( -1.32 ) = 0.0934   ---------- let this equation 2

so from equation 1 and 2

39-44/σ = -132

-5/σ = -1.32

σ  = -5 / - 1.32

σ  = 3.7879 ≈ 3.8

Therefore, the required standard deviation is 3.8

Option a) 3.8 is the correct answer

7 0
2 years ago
Your general speech topic is dog obedience, and you have arranged an interview with an authority. what is your next task?
valentinak56 [21]
It is to research about dog behavior
6 0
3 years ago
Mickey is a 12-year-old dialysis patient. Three times a week for the entire year he and his mother, Sue, drive 20 miles one way
gavmur [86]

Answer:

The right approach will be "$ 1123.2".

Explanation:

The number of miles to be used will be:

= 40 \ miles \ round \ trip\times  3 \ trips \ per \ week\times 52 weeks

= 6240 \ miles

Now,

The item deduction will be:

= Number \ of \ used \ miles\times 18 \ cents \ per \ mile

= 6240\times 1123.2

= 1123.2 ($)

4 0
3 years ago
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