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Marrrta [24]
2 years ago
15

A line with a slope of -3/4 that passes through the point (-14,4).

Mathematics
2 answers:
damaskus [11]2 years ago
6 0

Answer:

y=-3/4x-13/2

Step-by-step explanation:

This should be the answer, I am not 100% though

I did y-4=-3/4x(x+14)

klio [65]2 years ago
6 0
Y=-3/4 x (-14,4). Hope this helps!
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4 times 4 and 2 times8

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3 years ago
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What is the constant term of the quotient when 2x^3-3x^2 + 4x-2 is divided by x^2-x+2?
AlladinOne [14]

Answer:

  -1

Step-by-step explanation:

See the attachment for the polynomial long division. The constant in the quotient is -1.

_____

Here, there is a remainder of -x. If there were no remainder the constant in the quotient is the ratio of the constant in the dividend to the constant in the divisor: -2/2 = -1.

That could be a first guess in a "guess and check" solution approach.

<em>Guess</em>: first term of binomial quotient is (2x^3)/x^2 = 2x; last term of binomial quotient is -2/2 = -1. So, the quotient is guessed to be (2x -1).

<em>Check</em>: (2x -1)(x^2 -x +2) = 2x^3 -3x^2 +5x -2

Subtracting this from the actual dividend gives a remainder of -x. This has a lower degree than the divisor, so no further adjustment of the quotient is required.

6 0
3 years ago
Find the LCM of 6 and 15.<br> A) 6 <br> B) 15 <br> C) 30 <br> D) 90
erastovalidia [21]

Answer:

30

Step-by-step explanation:

the answer is 30 because if you count by 6 it would go 6,12,18,24,30,36,42 and if you go by 15 it would be 15,30,45,60,75,90..... and the only number that you see twice is 30 so the answer would be 30. Hope this helped...

3 0
2 years ago
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A garden measuring 9 meters by 4 meters is going to have a walkway constructed all around the perimeter, increasing the total ar
marysya [2.9K]

Answer:

3 metres

Step-by-step explanation:

Let the width of the pathway be x

Area: (9+2x)(4+2x)

36 + 8x + 18x + 4x²

4x² + 26x + 36

Increased area is 150:

4x² + 26x + 36 = 150

4x² + 26x - 114 = 0

2x² + 13x - 57 = 0

2x² + 19x - 6x - 57 = 0

x(2x + 19) - 3(2x + 19) = 0

(x - 3)(2x + 19) = 0

x = 3, x = -19/2

4 0
3 years ago
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The equation a=1/2(b^1+b^2)h can be determined the area, a, of a trapezoid with height, h, and base lengths, b^1 and b^2 Which a
Evgesh-ka [11]

The complete question is as follows.

The equation a = \frac{1}{2}(b_1 + b_2 )h can be used to determine the area , <em>a</em>, of a trapezoid with height , h, and base lengths, b_1 and b_2. Which are equivalent equations?

(a) \frac{2a}{h} - b_2 = b_1

(b) \frac{a}{2h} - b_2 = b_1

(c) \frac{2a - b_2}{h} = b_1

(d) \frac{2a}{b_1 + b_2} = h

(e) \frac{a}{2(b_1 + b_2)} = h

Answer: (a) \frac{2a}{h} - b_2 = b_1; (d) \frac{2a}{b_1 + b_2} = h;

Step-by-step explanation: To determine b_1:

a = \frac{1}{2}(b_1 + b_2 )h

2a = (b_1 + b_2)h

\frac{2a}{h} = b_1 + b_2

\frac{2a}{h} - b_2 = b_1

To determine h:

a = \frac{1}{2}(b_1 + b_2 )h

2a = (b_1 + b_2)h

\frac{2a}{(b_1 + b_2)} = h

To determine b_2

a = \frac{1}{2}(b_1 + b_2 )h

2a = (b_1 + b_2)h

\frac{2a}{h} = (b_1 + b_2)

\frac{2a}{h} - b_1 = b_2

Checking the alternatives, you have that \frac{2a}{h} - b_2 = b_1 and \frac{2a}{(b_1 + b_2)} = h, so alternatives <u>A</u> and <u>D</u> are correct.

4 0
3 years ago
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