Ask question

Ask question

All categories

3 years ago

9

On a recent day, 8 euros were worth $9 and 24 euros were worth $27. Write an equation of the form y=kx to show the between the n

umber of euros and the value in dollars. Sentence: ___________, where y is dollars and x is euros.

1 answer:

g100num [7]3 years ago

5 0

$9= k•8 euros so k=9/8=1.125
So for every 1 euro we have $1.125
y=1.125•x

$27=k•24 euros so k=28/24=1.166666667
y=1.67•x

You might be interested in

Sanja made a hole-in-one on the sixth hole of miniature golf 8 times and missed it 4 times. If Sanja attempts 24 more holes-in-o

hram777 [196]

Answer:

16 holes in ones

Step-by-step explanation:

I just did the guiz and got that one right

7 0

2 years ago

Read 2 more answers

What is the measure of

Anestetic [448]

It’s either 100 or 130

8 0

2 years ago

(2pm^-1q^0)^-4 • 2m ^-1 p^3 / 2pq^2

Montano1993 [528]

Answer:

$\dfrac{m^3}{16p^2q^2}$

Step-by-step explanation:

Given:

$(2pm^{-1}q^0)^{-4}\cdot \dfrac{ 2m^{-1} p^3}{2pq^2}$

1.

$m^{-1}=\dfrac{1}{m}$

2.

$q^0=1$

3.

$2pm^{-1}q^0=2p\cdot \dfrac{1}{m}\cdot 1=\dfrac{2p}{m}$

4.

$(2pm^{-1}q^0)^{-4}=\left(\dfrac{2p}{m}\right)^{-4}=\left(\dfrac{m}{2p}\right)^4=\dfrac{m^4}{(2p)^4}=\dfrac{m^4}{16p^4}$

5.

$m^{-1}=\dfrac{1}{m}$

6.

$2m^{-1} p^3=2\cdot \dfrac{1}{m}\cdot p^3=\dfrac{2p^3}{m}$

7.

$\dfrac{ 2m^{-1} p^3}{2pq^2}=\dfrac{\frac{2p^3}{m}}{2pq^2}=\dfrac{2p^3}{m}\cdot \dfrac{1}{2pq^2}=\dfrac{p^2}{mq^2}$

8.

$(2pm^{-1}q^0)^{-4}\cdot \dfrac{ 2m^{-1} p^3}{2pq^2}=\dfrac{m^4}{16p^4}\cdot \dfrac{p^2}{mq^2}=\dfrac{m^3}{16p^2q^2}$

8 0

2 years ago

3 pizzas for $ 16.50 what is the unit rate for one pizza

o-na [289]

The answer is 5.50$ you have to divide 16.50/ 3

8 0

2 years ago

Read 2 more answers

Determine the value of x.

harina [27]

Answer:

2

Step-by-step explanation:

7 0

2 years ago