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Kipish [7]
3 years ago
9

I need help with all of these questions can you help pls

Mathematics
1 answer:
Luden [163]3 years ago
6 0
For 3) 6/10 times 18
6/10 times 18/1 = 108/10= 54/5 or 272.5


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Round 409,184 to the nearest ten thousand?
olga nikolaevna [1]
How to round 409,184 to the nearest ten thousand 

409,184=410,000

so 409,184 rounded to the nearest ten thousand is 410,000
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if the volume of a cube of wood is 15.625 cm^3 and its mass is 10.00 grams show the calculation for the density of the cube
oee [108]
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4 years ago
A student records the repair cost for 22 randomly selected dryers. A sample mean of $98.78 and standard deviation of $15.49 are
Gelneren [198K]

Answer:

The critical value that should be used is T = 2.0796.

The 95% confidence interval for the mean repair cost for the dryers is between $91.912 and $105.648.

Step-by-step explanation:

We have the standard deviation for the sample, which means that the t-distribution is used to solve this question.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 22 - 1 = 21

95% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 21 degrees of freedom(y-axis) and a confidence level of 1 - \frac{1 - 0.95}{2} = 0.975. So we have T = 2.0796, which is the critical value that should be used.

The margin of error is:

M = T\frac{s}{\sqrt{n}} = 2.0796\frac{15.49}{\sqrt{22}} = 6.868

In which s is the standard deviation of the sample and n is the size of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 98.78 - 6.868 = $91.912

The upper end of the interval is the sample mean added to M. So it is 98.78 + 6.868 = $105.648

The 95% confidence interval for the mean repair cost for the dryers is between $91.912 and $105.648.

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PLEASE HELP!!!!!!
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