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Neporo4naja [7]

3 years ago

10

What is the Equation of the line of symmetry for the parabola represented by the equation y= -2(x-7)^2+11 Enter your answer as T

he correct equation, like this x=42

1 answer:

STatiana [176]3 years ago

3 0

Answer:

Step-by-step explanation:

Sing robbery and ur done

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At an appliance store, the price of a refrigerator is marked up 25% to $406.25.

likoan [24]

Answer:

$325

Step-by-step explanation:

5 0

2 years ago

Read 2 more answers

A car, initially at rest, accelerates at 2 meters/s/s. assuming the car starts from rest, how far will it travel in 10 s?

MrRa [10]

We shall use the formula for distance traveled:
s = ut + (1/2)at^2
where
u = initial velocity
t = time
a = acceleration.

Because
u = 0 (car starts from rest),
t = 10 s (travel tme),
a = 2 m/s^2 (acceleration), m
the di mstance traveled is
s = (1/2)*(2 m/s^2)*(10 s)^2 = (1/2)*2*100 = 100

Answer: 100 m

8 0

4 years ago

Mike has a large tropical fish collection.He gives 2/3 of his fish to a local high school. Then gives 2/5 of the remaining fish

joja [24]

If you divide the 2 in 3 you get .6 and if you divide 2 in 5 ou get ,4 now add them you and get 1 now add that 1 to 30 your answer should be 31

3 0

3 years ago

Fill in the table with the output values that represent the function y=4x+8 .

a_sh-v [17]

<span>y=4x+8 is a linear function with slope 4 and y-intercept 8.

If x=0, y=8; the y-intercept is (0,8).
If x=1, y=4(1)+8 = 12

If x=5, y=28

and so on</span>

7 0

4 years ago

You are a lifeguard and spot a drowning child 60 meters along the shore and 40 meters from the shore to the child. You run along

sukhopar [10]

Answer:

The lifeguard should run across the shore a distance of 48.074 m before jumpng into the water in order to minimize the time to reach the child.

Step-by-step explanation:

This is a problem of optimization.

We have to minimize the time it takes for the lifeguard to reach the child.

The time can be calculated by dividing the distance by the speed for each section.

The distance in the shore and in the water depends on when the lifeguard gets in the water. We use the variable x to model this, as seen in the picture attached.

Then, the distance in the shore is d_b=x and the distance swimming can be calculated using the Pithagorean theorem:

$d_s^2=(60-x)^2+40^2=60^2-120x+x^2+40^2=x^2-120x+5200\\\\d_s=\sqrt{x^2-120x+5200}$

Then, the time (speed divided by distance) is:

$t=d_b/v_b+d_s/v_s\\\\t=x/4+\sqrt{x^2-120x+5200}/1.1$

To optimize this function we have to derive and equal to zero:

$\dfrac{dt}{dx}=\dfrac{1}{4}+\dfrac{1}{1.1}(\dfrac{1}{2})\dfrac{2x-120}{\sqrt{x^2-120x+5200}} \\\\\\\dfrac{dt}{dx}=\dfrac{1}{4} +\dfrac{1}{1.1} \dfrac{x-60}{\sqrt{x^2-120x+5200}} =0\\\\\\ \dfrac{x-60}{\sqrt{x^2-120x+5200}} =\dfrac{1.1}{4}=\dfrac{2}{7}\\\\\\ x-60=\dfrac{2}{7}\sqrt{x^2-120x+5200}\\\\\\(x-60)^2=\dfrac{2^2}{7^2}(x^2-120x+5200)\\\\\\(x-60)^2=\dfrac{4}{49}[(x-60)^2+40^2]\\\\\\(1-4/49)(x-60)^2=4*40^2/49=6400/49\\\\(45/49)(x-60)^2=6400/49\\\\45(x-60)^2=6400\\\\$

$x$

As $d_b=x$ , the lifeguard should run across the shore a distance of 48.074 m before jumpng into the water in order to minimize the time to reach the child.

7 0

3 years ago