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harina [27]
3 years ago
7

The midpoints of the hexagon are connected to form another hexagon, this pattern continues indefinitely. If the area of the 99th

hexagon formed by this pattern is 1, what is the area of the original hexagon?
Mathematics
2 answers:
jarptica [38.1K]3 years ago
7 0

Answer:

  • (4/3)⁹⁸ units²

Step-by-step explanation:

  • <em>Regular hexagons have a property that cutting off the triangles obtained by joining the midpoints of consecutive sides leaves a hexagon of 3/4 of the area.</em>

This means the area of each hexagon inside out starting from the one with unit area is 4/3 of the previous one.

  • 99 ⇒ 1
  • 98 ⇒ 1*4/3
  • 97 ⇒ 1*(4/3)²
  • ...
  • 1 ⇒ (4/3)⁹⁹⁻¹

<u>The original hexagon has the area of:</u>

  • (4/3)⁹⁸ units²
Ivanshal [37]3 years ago
7 0

Answer:

(4/3)^98units.

Step-by-step explanation:

By hexagonal property in which cut off the triangles obtained be the joining of m.p of adjacent sides which left 3/4 of total area.

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Answer:

The points that are exactly 10 units from the point (–8, –2) are (2, –2)  and (–8, 8).

Step-by-step explanation:

The distance formula is;

                               d= \sqrt{( x_{2}-x_{1} )^{2}-(y_{2} -y_{1} )^{2}   }

So for distance between: (–8, –2)  and (2, –2) is:

                             d=  \sqrt{( 2-(-8))^{2}-(-2 -(-2) )^{2}   }

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Similarly for distance between: (–8, –2) and (–8, 8) is,

                                d=  \sqrt{( -8-(-8))^{2}-(8 -(-2) )^{2}   }

                               d= \sqrt{100}

                               d= 10 unit

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