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snow_lady [41]
3 years ago
10

Hi, I need the are to this question, I just need to show my work btw​

Mathematics
1 answer:
Nana76 [90]3 years ago
6 0
What is the question?
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The ratio of the number of people who own a cat to the number of people who own a dog is 5:7. If there are 12 more people who ow
topjm [15]

Answer:

30 people own a cat

Step-by-step explanation:

6 0
3 years ago
Peter bought 9 packs of pencils. Each pack has 10 pencils in it. If he lost 18 pencils, how many pencils
Sindrei [870]

Answer:

a 72

Step-by-step explanation:

9x10=90, so in total he has 90 pencils. if he loses 18 of them that's 90-18 which is 72.

4 0
3 years ago
Jim thinks that the value of a baseball card can be modeled by a decay formula and that the value will decrease at a rate of 0.2
Sindrei [870]

Answer: $244.55

A = $250  ;  r=0.002   t= 11   [From 2007 to 2018 , t=2018-2007]

6 0
1 year ago
Why does a y-intercept not count as a zero?
Genrish500 [490]

Answer:

It only counts as a zero when the y-intercept is (0,0).

Step-by-step explanation:

The zeros of a quadratic function are always written as (x,0), while the y-intercept is always written as (0,y). Therefore, in order for a y-intercept to be a zero, it must be (0,0), because the y-coordinate in any zero is 0. At any other time, the y-intercept is not a zero.

7 0
4 years ago
Find the general solution of the following ODE: y' + 1/t y = 3 cos(2t), t > 0.
Margarita [4]

Answer:

y = 3sin2t/2 - 3cos2t/4t + C/t

Step-by-step explanation:

The differential equation y' + 1/t y = 3 cos(2t) is a first order differential equation in the form y'+p(t)y = q(t) with integrating factor I = e^∫p(t)dt

Comparing the standard form with the given differential equation.

p(t) = 1/t and q(t) = 3cos(2t)

I = e^∫1/tdt

I = e^ln(t)

I = t

The general solution for first a first order DE is expressed as;

y×I = ∫q(t)Idt + C where I is the integrating factor and C is the constant of integration.

yt = ∫t(3cos2t)dt

yt = 3∫t(cos2t)dt ...... 1

Integrating ∫t(cos2t)dt using integration by part.

Let u = t, dv = cos2tdt

du/dt = 1; du = dt

v = ∫(cos2t)dt

v = sin2t/2

∫t(cos2t)dt = t(sin2t/2) + ∫(sin2t)/2dt

= tsin2t/2 - cos2t/4 ..... 2

Substituting equation 2 into 1

yt = 3(tsin2t/2 - cos2t/4) + C

Divide through by t

y = 3sin2t/2 - 3cos2t/4t + C/t

Hence the general solution to the ODE is y = 3sin2t/2 - 3cos2t/4t + C/t

3 0
3 years ago
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