Question

Help me please! will mark brainliest for the correct answer

Answer 1

Answer:

see explanation

Step-by-step explanation:

Using the rules of exponents

$a^{m}$ × $a^{n}$ ⇔ $a^{(m+n)}$

$(a^m)^{n}$ = $a^{mn}$

$a^{-m}$ ⇔ $\frac{1}{a^{m} }$

Thus

$4^{3x-2}$

= $4^{3x}$ × $4^{-2}$

= $(4^3)^{x}$ × $4^{-2}$

= $64^{x}$ × $\frac{1}{4^2}$

= $\frac{64^{x} }{16}$ ← as required