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2 years ago

A grocer can buy strawberries for $1.38 per pound. write an equation relating c, the cost, and p, the pounds of strawberries.

Mathematics

1 answer:

slamgirl [31]2 years ago

5 0

Answer:

1.38p=C

Step-by-step explanation:

each pound is $1.38 and pounds is p they have to equal to C, the total.

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Temka [501]

About 15 inches- by pythag- $\sqrt{16^{2} - 5^{2} }$

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2 years ago

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Is the number 15 prime or composite? prime composite Please help me. Will mark brainiest! Thats okay if you don't know don't ans

elixir [45]

Answer:

Hey there!

15 is composite. A composite number has factors other than one and itself. 15 has factors 3 and 5.

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3 3/4+ (-4 1/3)<br> Simplify

IgorC [24]

Answer:

-7/12 in decimal form it would be -0.583

Step-by-step explanation:

convert the mixed number to an improper fraction

(when there's a + in front of an expression in parentheses the expression remains the same)

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3 years ago

Consider a population p of field mice that grows at a rate proportional to the current population, so that dp dt = rp. (note: re

krok68 [10]

This is the concept of differential equations, given that
dp/dt=rp
then:
dp/p=rdt
thus:
ln p=rt+C
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P=Ke^(rt)
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3 years ago

GAMING In a video game, the user navigates a character across an unknown land using a map. On the map, the distance between the

soldi70 [24.7K]

The question is an illustration of scale drawing

The character have to travel 8.5 km in the game to visit all three destinations and return to their starting point

<h3>How to calculate the actual distance</h3>

The distance on the map are given as:

A =2 cm

B = 8 cm

C = 7 cm

The total distance on the map would be:

$Total =2cm + 8cm + 7cm$

$Total =17cm$

The actual distance between the store and the dungeon is 4 kilometers.

This means that:

$B' =4km$

So, we have:

$Scale = B : B'$

$Scale = 8cm : 4km'$

Represent the required actual distance with x.

So, we have:

$17cm : x = 8cm : 4km$

Express as fraction

$\frac{x}{17} = \frac 48$

Multiply both sides by 17

$x = \frac 48 * 17$

$x = 8.5$

Hence, the actual distance travelled is 8.5 km