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poizon [28]
3 years ago
5

How would you find an interquartile range with just numbers?

Mathematics
1 answer:
Stolb23 [73]3 years ago
8 0

Answer:

IQR is 3.5

Step-by-step explanation:

<u>Step 1: Organize the numbers in numerical order</u>

0,0,2,2,3,4,6,8

<u>Step 2: Break the set up into quartiles (4 parts)</u>

0 0 | 2 2 | 3 4 | 6 8

<u>Step 3: Find the average of each quartile</u>

0 | 2 | 3.5 | 7

<u>Step 4: Find the IQR (Q3-Q1)</u>

3.5-0=3.5

Therefore, the IQR is 3.5

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Write the equation of the line that passes through the points (-6,5) and (3,−5). Put your answer in fully reduced point-slope fo
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Answer:

\displaystyle y-5=-\frac{10}{9}(x+6)

Or:

\displaystyle y+5=-\frac{10}{9}(x-3)

Step-by-step explanation:

We want to write the equation of a line that passes through the points (-6, 5) and (3, -5) in point-slope form.

Point-slope form is given by:

y-y_1=m(x-x_1)

Thus, first, we need to find the slope. We can use the slope formula:

\displaystyle m=\frac{\Delta y}{\Delta x}=\frac{(-5)-(5)}{(3)-(-6)}=\frac{-10}{9}=-\frac{10}{9}

Next, we can use either of the two given points. I'll use (-6, 5). So, let (-6, 5) be (<em>x₁, y₁</em>). Substitute:

\displaystyle y-(5)=-\frac{10}{9}(x-(-6))

Or, fully simplified:

\displaystyle y-5=\frac{-10}{9}(x+6)

Using the other point, we will acquire:

\displaystyle y-(-5)=-\frac{10}{9}(x-(3))

Or, simplified:

\displaystyle y+5=-\frac{10}{9}(x-3)

8 0
3 years ago
What are the steps to solve an inequality like: |n + 8| &gt; 3 ??????
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