Answer:
none of the above
Step-by-step explanation:
You can try the points in the equations (none works in any equation), or you can plot the points and lines (see attached). <em>You will not find any of the offered answer choices goes through the given points</em>.
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You can start with the 2-point form of the equation of a line. For points (x1, y1) and (x2, y2) that equation is ...
y = (y2 -y1)/(x2 -x1)·(x -x1) +y1
Filling in the given points, we get ...
y = (3 -1)/(2 -4)·(x -4) +1
y = 2/(-2)(x -4) +1 . . . . . simplify a bit
y = -x +4 +1 . . . . . . . . . simplify more
y = -x +5 . . . . . . . . . . . slope-intercept form
Divide to get a low form of a fraction.
13 divide by 13 = 1
78/13 = 6
1/6 would therefore, be the lowest form
Answer:
sheeeeeeeeeeeeeesh
Step-by-step explanation:
Answer:
2x+50 and 5x-55 both are congruent or have same measure.
Step-by-step explanation:
Since we want to prove that both lines are parallel, this means no theorems that involve with parallel lines apply here.
First of, we know that AC is a straight line and has a measure as 180° via straight angle.
x+25 and 2x+50 are supplementary which means they both add up to 180°.
Sum of two measures form a straight line which has 180°.
Therefore:-
x+25+2x+50=180
Combine like terms:-
3x+75=180
Subtract 75 both sides:-
3x+75-75=180-75
3x=105
Divide both sides by 3.
x=35°
Thus, x = 35°
Then we substitute x = 35 in every angles/measures.
x+25 = 35°+25° = 60°
2x+50 = 2(35°)+50° = 70°+50° = 120°
5x-55 = 5(35°)-55 = 175°-55° = 120°
Since 2x+50 and 5x-55 have same measure or are congruent, this proves that both lines are parallel.
55 percent, I believe. Hope this helps!
