B = 2 + 2H
A = 20 ft^2
H = H

Since the Area of a Triangle is Base * Height then the formula should be:
A = BH
20 = H(2+2H)
20 = 2H^2 + 2H
0 = 2H^2 + 2H - 20

Find the zeros of the quadratic equation through substituting the values of a,b, and c. You will get the zeros of x = 2.7 and -3.7. The only thing that would make sense is you use the x=2.7 because there are no negative heights.

Since b = 2h+2
b= 2(2.7) + 2
b= 5.4 + 2
b=7.4

I don't know where you got 4 and 10, but what I got is different.

8 0

3 years ago

<img src="https://tex.z-dn.net/?f=%5Csqrt%7B272%7D" id="TexFormula1" title="\sqrt{272}" alt="\sqrt{272}" align="absmiddle" class

lozanna [386]

√272 is a real number, and the simplified expression of √272 is 4√17

<h3>How to simplify the expression?</h3>

The expression is given as:

√272

Expand

√272 = √16 * 17

Take the square root of 16

√272 = 4√17

Hence, the simplified expression of √272 is 4√17