Answer:
Step-by-step explanation:
Product of 5 and a number: 5n
Six more than that would be 5n + 6
Finally, "six more than the product of 5 and a number, decreased by one" would be
5n + 6 - 1, or 5n + 5
hi
-16t²+250 = 75
-16t² = 75 -250
-16t² = -175
t² = -175 /-16
t² = 175/16
Here there si two solutions : t = 
and t = -
However, as time cannot rewind, we will keep only positive solution
So t =
in seconds it will be : 3.3 seconds
Answer:
96π
Step-by-step explanation:
V=96π
Looks like a badly encoded/decoded symbol. It's supposed to be a minus sign, so you're asked to find the expectation of 2<em>X </em>² - <em>Y</em>.
If you don't know how <em>X</em> or <em>Y</em> are distributed, but you know E[<em>X</em> ²] and E[<em>Y</em>], then it's as simple as distributing the expectation over the sum:
E[2<em>X </em>² - <em>Y</em>] = 2 E[<em>X </em>²] - E[<em>Y</em>]
Or, if you're given the expectation and variance of <em>X</em>, you have
Var[<em>X</em>] = E[<em>X</em> ²] - E[<em>X</em>]²
→ E[2<em>X </em>² - <em>Y</em>] = 2 (Var[<em>X</em>] + E[<em>X</em>]²) - E[<em>Y</em>]
Otherwise, you may be given the density function, or joint density, in which case you can determine the expectations by computing an integral or sum.
