Please answer correctly !!!!!!!!!!!!!!! Will mark Brianliest !!!!!!!!!!!!!!!!!!!!
1 answer:
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Answer:
B
Step-by-step explanation:
The range of a function f, would contain outputs that the function can output, or in other words, y-values.
Generally we use inequalities to describe functions that are continuous (not always the case) over a certain interval because using inequalities, doesn't just mean that the inequality has some outputs, but rather every value that satisfies the given inequality, should be an output.
For example if the function f(x) only outputs: 1, 2, 3, 4
It would be invalid to say the range is:
because saying this is the range, would imply that all values between 1 and 4 (including 1 and 4), are in the range. Meaning that 1.2, 1.3, 1.4, etc... are also in this range, but they're not since the function doesn't output these y-values.
Now looking onto the graph provided, we only want to focus on the outputs aka y-values.
Looking at the graph, we can see that the y-values are: 1, -4, 5, -3, and -3.
Notice that we actually have a duplicate y-value, and whenever we have this, we don't state it "twice" in the range, since the range is just telling us of y-values the function can output, and not how many times it occurs.
Thus the range is: -4, -3, 1, and 5
So "b" would be the correct option.
Note: "D" would be the correct choice for the domain of this function (like the range, except it deals with x-values)
Answer:
- <u><em>The height of the missing rectangle is 0.15</em></u>
Explanation:
The image attached has the mentioned <em>histogram</em>.
Such histogram presents the relative frequencies for the clases [0,1], [1,2],[2,3], [4,5], and [5,6] Silver in ppm.
Only the rectangle for the class [3,4] is missing.
The height of each rectangle is the relative frequency of the corresponding class.
The relative frequencies must add 1, because each relative frequency is calculated dividing the absolute class frequency by the total number in the sample; hence, the sum of all the relative frequencies is equal to the total absolute class frequencies divided by the same number, yielding 1.
In consequence, you can sum all the known relative frequencies and subtract from 1 to get the missing relative frequency, which is the height of the missing rectangle.
<u>1. Sum of the known relative frequencies</u>:
- 0.2 + 0.3 + 0.15 + 0.1 + 0.1 = 0.85
<u>2. Missing frequency</u>:
- 1 - 0.85 = 0.15
<u>3. Conclusion</u>:
- The height of the missing rectangle is 0.15
