Answer:
95/4
Step-by-step explanation:
Given,
a/b =2/3
Therefore, 2a²+3b²/a²+b² = ?
We get,
a/b = 2/3
So, we can write
a = 2 and b = 3
Now,
2×(2)² + 3×(3)²/(2)² + (3)² [Putting the values of a and b]
= 2×4 + 3×9/4 + 9
= 8 +27/4 + 9
= (32+27+36)/4 [ Taking L.C.M, we get 4]
= 95/4
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Answer:
we know that, Volume of cube=a³
Let volume of 1st cube be 2x with side a and other be x with side A (according to given ratio)
Step-by-step explanation:
ATQ: 2x=a³ and, x=A³
a=³√2x and, A=x
we know that, surface area of cube is 6a²
Thus, surface area of 1st cube = 6(³√2x)²
= 6³√4x²
Surface area of 2nd cube=6(x)²=6x²
Ratio of S.A=(6³√4x²)÷(6x²)
Ratio of S.A=³√4:1
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Answer:
See below
Step-by-step explanation:
1) x = 4
2) x = 12
3) x = 45
4) x= 5.56
5) x = 35/18
6) x = 3/2
7) x = 19/3
8) x = 3/35
9) x = 47/5
10) x+4 = 17/2 so x = 9/2
Answer:
yes
Step-by-step explanation:
yes it will
Answer:
![f'(x) = \frac{2{x}^{2}}{ \sqrt[3]{( {x}^{3} - 8) } }](https://tex.z-dn.net/?f=%20f%27%28x%29%20%3D%20%20%20%5Cfrac%7B2%7Bx%7D%5E%7B2%7D%7D%7B%20%5Csqrt%5B3%5D%7B%28%20%7Bx%7D%5E%7B3%7D%20%20-%208%29%20%7D%20%7D)
Step-by-step explanation:
![f(x) = ( {x}^{3} - 8)^{ \frac{2}{3} } \\ \\ f'(x) = \frac{2}{3} ( {x}^{3} - 8)^{ \frac{2}{3} - 1 } (3 {x}^{2} - 0) \\ \\ f'(x) = \frac{2}{3} ( {x}^{3} - 8)^{ \frac{2 - 3}{3} } \times 3 {x}^{2} \\ \\ f'(x) = 2{x}^{2}( {x}^{3} - 8)^{ \frac{ - 1}{3} } \\ \\ f'(x) = \frac{2{x}^{2}}{( {x}^{3} - 8)^{ \frac{ 1}{3} } } \\ \\ \huge \red{ \boxed{ f'(x) = \frac{2{x}^{2}}{ \sqrt[3]{( {x}^{3} - 8) } } }}](https://tex.z-dn.net/?f=f%28x%29%20%3D%20%28%20%7Bx%7D%5E%7B3%7D%20%20-%208%29%5E%7B%20%5Cfrac%7B2%7D%7B3%7D%20%7D%20%20%5C%5C%20%20%5C%5C%20f%27%28x%29%20%3D%20%20%5Cfrac%7B2%7D%7B3%7D%20%28%20%7Bx%7D%5E%7B3%7D%20%20-%208%29%5E%7B%20%5Cfrac%7B2%7D%7B3%7D%20-%201%20%7D%20%283%20%7Bx%7D%5E%7B2%7D%20%20-%200%29%20%5C%5C%20%20%5C%5C%20f%27%28x%29%20%3D%20%20%5Cfrac%7B2%7D%7B3%7D%20%28%20%7Bx%7D%5E%7B3%7D%20%20-%208%29%5E%7B%20%5Cfrac%7B2%20-%203%7D%7B3%7D%20%20%7D%20%20%5Ctimes%203%20%7Bx%7D%5E%7B2%7D%20%5C%5C%20%20%5C%5C%20f%27%28x%29%20%3D%20%202%7Bx%7D%5E%7B2%7D%28%20%7Bx%7D%5E%7B3%7D%20%20-%208%29%5E%7B%20%5Cfrac%7B%20-%201%7D%7B3%7D%20%20%7D%20%5C%5C%20%20%5C%5C%20f%27%28x%29%20%3D%20%20%20%5Cfrac%7B2%7Bx%7D%5E%7B2%7D%7D%7B%28%20%7Bx%7D%5E%7B3%7D%20%20-%208%29%5E%7B%20%5Cfrac%7B%201%7D%7B3%7D%20%20%7D%20%7D%20%5C%5C%20%20%5C%5C%20%5Chuge%20%5Cred%7B%20%5Cboxed%7B%20f%27%28x%29%20%3D%20%20%20%5Cfrac%7B2%7Bx%7D%5E%7B2%7D%7D%7B%20%5Csqrt%5B3%5D%7B%28%20%7Bx%7D%5E%7B3%7D%20%20-%208%29%20%7D%20%7D%20%7D%7D)
