Answer:
81 times the original size
Step-by-step explanation:
AA0ktA=3A0=?=?=25hours=A0ekt
Substitute the values in the formula.
3A0=A0ek⋅25
Solve for k. Divide each side by A0.
3A0A0=e25k
Take the natural log of each side.
ln3=lne25k
Use the power property.
ln3=25klne
Simplify.
ln3=25k
Divide each side by 25.
ln325=k
Approximate the answer.
k≈0.044
We use this rate of growth to predict the number of bacteria there will be in 100 hours.
AA0ktA=3A0=?=ln325=100hours=A0ekt
Substitute in the values.
A=A0eln325⋅100
Evaluate.
A=81A0
At this rate of growth, we can expect the population to be 81 times as large as the original population.
Answer:
I think it's 8 - ab but I'm not really sure
Answer:
a) 100 $
b) 566,66 $
c) 566,66 $
Step-by-step explanation:
Mak 85,000 $ /per year, means 85000/12 per month that is 7083,33
8% of 7083,33 is 566,66 $ . Then
a) 200 < 566,33 then my company will contribute with 0,5*200 = 100 $
b) If I contribute with 830 $ ( 830 > 566,66 ) then my company will contribute with 566,66 $ the biggest amount
c) 566,66 s the maximm amount of money
Answer:
k = 6
Step-by-step explanation:
Given f(x) then f(x + a) is a horizontal translation of f(x)
• If a > 0 then a shift to the left of a units
• If a < 0 then a shift to the right of a units
Here g(x) is the graph of f(x) shifted 6 units to the left
Then
g(x) = f(x + 6) → with k = 6
