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3 years ago

Which statement below shows the best use of friendly numbers to estimate the value of 27 x 4

Mathematics

2 answers:

Romashka-Z-Leto [24]3 years ago

4 0

Yeah, 27 x 4=108 if thats what youre asking for

topjm [15]3 years ago

3 0

27x4=108 is the best form and answer

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45 minutes to 1 hour ratio

Mariana [72]

$h-hour(s)\\min-minute(s)\\\\1h=60min\to45min=\dfrac{45}{60}h=\dfrac{45:15}{60:15}h=\dfrac{3}{4}h\\\\45min\ to\ 1h=\dfrac{3}{4}h:1h=\huge\boxed{3:4}$

7 0

4 years ago

Read 2 more answers

jimmy is moving to a new apartment. he fills a box with 4 books, 5 DVDs, and 2 CD's. when he starts unpacking his new place he p

pav-90 [236]

Answer:

$\frac{2}{11}$

Step-by-step explanation:

First, find the probability of him pulling out a book.

There are 11 objects in total, and there are 4 books.

So, the probability of pulling out a book is $\frac{4}{11}$

Next, find the probability of him pulling out a DVD after.

Since a book was taken out, there are only 10 objects left. There are 5 DVDs.

So, the probability of pulling out a DVD is $\frac{5}{10}$ , or simplified to $\frac{1}{2}$

To find the probability that this happens in order, multiply the probabilities:

$\frac{4}{11}$ x $\frac{1}{2}$

= $\frac{2}{11}$

So, the probability is $\frac{2}{11}$

7 0

3 years ago

A rectangular piece of metal is 25 in longer than it is wide. Squares with sides 5 in long are cut from the four corners and the

Licemer1 [7]

Answer:

The original length was 41 inches and the original width was 16 inches

Step-by-step explanation:

Let

x ----> the original length of the piece of metal

y ----> the original width of the piece of metal

we know that

When squares with sides 5 in long are cut from the four corners and the flaps are folded upward to form an open box

The dimensions of the box are

$L=(x-10)\ in\\W=(y-10)\ in\\H=5\ in$

The volume of the box is equal to

$V=(x-10)(y-10)5$

$V=930\ in^3$

$930=(x-10)(y-10)5$

simplify

$186=(x-10)(y-10)$ -----> equation A

Remember that

The piece of metal is 25 in longer than it is wide

$x=y+25$ ----> equation B

substitute equation B in equation A

$186=(y+25-10)(y-10)$

solve for y

$186=(y+15)(y-10)\\186=y^2-10y+15y-150\\y^2+5y-336=0$

Solve the quadratic equation by graphing

using a graphing tool

The solution is y=16

see the attached figure

Find the value of x

$x=16+25=41$

therefore

The original length was 41 inches and the original width was 16 inches

3 0

3 years ago

What is the exact distance from (−4, −2) to (4, 6)?

Gekata [30.6K]

The distance between any two points is:

d^2=(x2-x1)^2+(y2-y1)^2

d^2=(6--2)^2+(4--4)^2

d^2=8^2+8^2

d^2=64+64

d^2=128

d=√128 units

6 0

4 years ago

How to prove two equations have infinite solutions?

laiz [17]

To prove two equations have infinite solutions, you have to prove that those two equations are the same equations, but in a different form.

For example: Prove the equations are infinite
5y=2x+7
10y=4x+14
If you multiply the first equation by 2, and substitiute any of the numbers, you will get 0=0

6 0

3 years ago