Answer:
1. x= - 20/13
2. 7x-21
Step-by-step explanation:
Answer:
P(A∣D) = 0.667
Step-by-step explanation:
We are given;
P(A) = 3P(B)
P(D|A) = 0.03
P(D|B) = 0.045
Now, we want to find P(A∣D) which is the posterior probability that a computer comes from factory A when given that it is defective.
Using Bayes' Rule and Law of Total Probability, we will get;
P(A∣D) = [P(A) * P(D|A)]/[(P(A) * P(D|A)) + (P(B) * P(D|B))]
Plugging in the relevant values, we have;
P(A∣D) = [3P(B) * 0.03]/[(3P(B) * 0.03) + (P(B) * 0.045)]
P(A∣D) = [P(B)/P(B)] [0.09]/[0.09 + 0.045]
P(B) will cancel out to give;
P(A∣D) = 0.09/0.135
P(A∣D) = 0.667
Answer: I'm pretty sure this is a direct relationship
Answer:
9/100, 9%
Step-by-step explanation:
0.09 is equal to 9/100
0.09 is equal to 9 percent
Answer:
y = 
Step-by-step explanation:
Given
x(y + 2) = 3x + y ← distribute parenthesis on left side
xy + 2x = 3x + y ( subtract 2x from both sides )
xy = x + y ( subtract y from both sides )
xy - y = x ← factor out y from each term on the left side )
y(x - 1) = x ← divide both sides by (x - 1)
y =
